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3 years ago

Which graph is a quadratic graph? The answer is Graph A

Mathematics

1 answer:

Snezhnost [94]3 years ago

4 0

Answer:

graph a

Step-by-step explanation:

i know

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>>>>>LOTS OF POINTS<<<<

Lynna [10]

Answer:

4.9 cm

Step-by-step explanation:

To solve this problem you would use the power of a point formula where two chords intersect in the interior of a circle. We get the equation:

7 * 7 = 10 *x

49 = 10x

x = 4.9 cm

6 0

3 years ago

Read 2 more answers

What is the slope if y+2=3/2(x+7)

Ymorist [56]

The slope for y+2=3/2(x+7) is m=3/2

3 0

4 years ago

Which graph represents the solution for the open sentence 3|p| – 5 < 7.

BabaBlast [244]

3p-5<7

add 5 to both sides

3p<12

divide 3 to both sides

p<4
the second graph B

6 0

4 years ago

Read 2 more answers

Name the property the equation illustrates.<br> (ab)3 = a (63)<br> Accociative Property of addition

Delvig [45]

<h3><u>Question:</u></h3>

Name the property the equation illustrates

(ab)3 = a(b3)

A. Commutative property of addition

B. Associative property of Multiplication

C. Associative Property of Addition

D. Inverse Property of Multiplication

<h3><u>Answer:</u></h3>

Associative property of Multiplication

<h3><u>Solution:</u></h3>

From given equation

(ab)3 = a(b3)

We have to find the property used here

We find the brackets are interchanged

So here, given is a multiplication equation

Therefore, Associative property of Multiplication is used

<h3><u>Associative property of Multiplication:</u></h3>

This property says that when we are multiplying it does not matter where you put the parenthesis

The result will be same wherever we put the parenthesis in multiplying two or more numbers

Which means,

$a \times (b \times c) = (a \times b) \times c$

Therefore, from given,

$a \times (b \times 3) = (a \times b) \times 3$

Thus associative property of multiplication is used

8 0

4 years ago

can someone please help and explain to me on how to do this geometry question please?! Thank youuuuu!!! ❤

qaws [65]

There are 13 angles.
We know that $m\angle4=112$ and $m\angle12=105$ (11 angles)

1.

$m\angle2+m\angle3+m\angle4=180\qquad\qquad\text{linear angles}\\\\m\angle3+m\angle3+m\angle4=180\qquad\qquad m\angle2=m\angle3\\\\2m\angle3+m\angle4=180\\\\2m\angle3+112=180\\\\2m\angle3=180-112\\\\2m\angle3=68\quad|:2\\\\\boxed{m\angle3=34=m\angle2}$

(9 angles)

2.

$m\angle3+m\angle12+m\angle11=180\qquad\qquad\text{triangle}\\\\34+105+m\angle11=180\\\\139+m\angle11=180\\\\m\angle11=180-139\\\\\boxed{m\angle11=41}$

(8 angles)

3.

$m\angle12+m\angle13=180\qquad\qquad\text{linear angles}\\\\105+m\angle13=180\\\\m\angle13=180-105\\\\\boxed{m\angle 13=75}$

(7 angles)

4.

$m\angle1+m\angle2+m\angle13=180\qquad\qquad\text{triangle}\\\\m\angle1+34+75=180\\\\m\angle1+109=180\\\\m\angle1=180-109\\\\\boxed{m\angle1=71}$

(6 angles)

5.

$m\angle9=m\angle11\qquad\qquad\text{vertical angles}\\\\\boxed{m\angle9=41}$

(5 angles)

6.

$m\angle10+m\angle11=180\qquad\qquad\text{linear angles}\\\\m\angle10+41=180\\\\m\angle10=180-41\\\\\boxed{m\angle10=139}$

(4 angles)

7. $a||b\text{ and } c||d$ so we have a parallelogram.

$m\angle4+m\angle5=180\qquad\text{consecutive angles are supplementary}\\\\112+m\angle5=180\\\\m\angle5=180-112\\\\\boxed{m\angle5=68}$

(3 angles)

$m\angle8=m\angle5\qquad\qquad\text{opposite angels are congruent}\\\\\boxed{m\angle8=68}$

(2 angles)

8.

$m\angle7+m\angle8+m\angle9=180\qquad\qquad\text{triangle}\\\\m\angle7+68+41=180\\\\m\angle7+109=180\\\\m\angle7=180-109\\\\\boxed{m\angle7=71}$

(1 angle)

9.

$m\angle1+m\angle5+m\angle6=180\qquad\qquad\text{triangle}\\\\71+68+m\angle6=180\\\\139+m\angle6=180\\\\m\angle6=180-139\\\\\boxed{m\angle6=41}$

6 0

3 years ago