Answer:
(0,1) , (2,4) , (4,7)
Explanation:
convert the equation into slope-intercept form (this would be y=3/2x+1)
now plug in random numbers for x and solve for y by multiplying them by 3/2 and adding 1.
Both 17/10 and 2 4/5 should be rounded up in preparation for this estimation.
17/10 is close to 2 and 2 4/5 is close to 3. Thus, your estimated answer should be
2/3, or approx. 0.6666....
Exact answer: divide 17/10 by 14/5. LCD is 10, so convert 14/5 to 28/10.
Now divide 17/10 by 28/10. Answer: 17/28 = approx. = 0.607 approx.
These two results are comparable: 0.6666.... and 0.6071 ....
<span>The problem is to calculate the angles of the triangle. However, it is not clear which angle you have to calculate, so we are going to calculate all of them
</span>
we know that
Applying the law of cosines
c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]
a=12.5
b=15
c=11
so
cos C=[a²+b²-c²]/[2*a*b]---> cos C=[12.5²+15²-11²]/[2*12.5*15]
cos C=0.694------------> C=arc cos (0.694)-----> C=46.05°-----> C=46.1°
applying the law of sines calculate angle B
15 sin B=11/sin 46.1-----> 15*sin 46.1=11*sin B----> sin B=15*sin 46.1/11
sin B=15*sin 46.1/11-----> sin B=0.9826----> B=arc sin (0.9826)
B=79.3°
calculate angle A
A+B+C=180------> A=180-B-C-----> A=180-79.3-46.1----> A=54.6°
the angles of the triangle are
A=54.6°
B=79.3°
C=46.1°
Step-by-step explanation:
you know that QPS adds up to 47
so the sum of RPS and QPR shoukd = 47
(3x - 38) + (7x - 95) = 47
you then solve for x then you can use that to find QPR
I believe that the zeros would be -2 and -6, assuming that the first 2 that you wrote in the equation is supposed to be a power to the x.
