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Talja [164]
3 years ago
14

Add. 1/2+(−3/5) can u help me

Mathematics
2 answers:
attashe74 [19]3 years ago
6 0
Exact form: -1/10

decimal form: -0.1
icang [17]3 years ago
6 0
-0.1 is the answer! hope this helps
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Hi!!!! Can someone please help me answer this math question??
GalinKa [24]
The shortcut is the hypotenuse of a right triangle with legs 6 and 8, so 6²+8²=c²

36+64=c
100=c²
c=10.
so he traveled 6+8+10=24km
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4 years ago
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What is the pay earned for 27 hours at $4.65 per hour?
Stella [2.4K]

Answer:

$125.55

Step-by-step explanation:

All you do is multiply your earned per hour by total hours.

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(PLEASE HELP)<br> Find measurement for angles for 1 and 2
katovenus [111]

Answer:

Angle 1 is = 54° ( vertically opposite angles)

Angle 2 is = Angle 1 (corresponding angles are equal)

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7 0
3 years ago
The length of a rectangle is 2 ft longer than its width.
tino4ka555 [31]

Hi! I'm happy to help!

To solve this, we first need to look at the perimeter equation:

P=2L+2W

We don't know our length, so we can represent it with x. Since our width is 2 feet shorter than x, we can represent it with x-2. Now, we plug these values into our equation:

56=2x+(2(x-2))

Let's simplify what the width is by multiplying:

56=2x+2x-4

Now, let's combine our 2xs

56=4x-4

Now, we just need to solve for x in order to find our length and width.

First, we need to isolate x on one side of the equation. We can do this by adding 4 to both sides:

56=4x-4

+4      +4

60=4x

Now, all we have to do is divide both sides by 4 and x will be fully isolated:

60=4x

÷4  ÷4

15=x

Now that we know x, let's plug this into our previous equations:

L=x=15

<u>L=15</u>

W=x-2=15-2=13

<u>W=13</u>

To verify our answers, we can plug this into our perimeter equation:

56=2(15)+2(13)

56=30+36

56=56

After double checking our answers, we know that our length is 15 and our width is 13.

I hope this was helpful, keep learning! :D

5 0
3 years ago
A manufacturer wants to make open tin boxes from pieces of tin with dimensions 8 in. by 15 in. by cutting equal squares from the
Stells [14]

Answer:

\frac{5}{3} in

Step-by-step explanation:

Let x be the side of square.

Length of box=8-2x

Width of box=15-2x

Height of box=x

Volume of box=L\times B\times H

Substitute the values then we get

Volume of box=V(x)=(8-2x)(15-2x)x=(15x-2x^2)(8-2x)

V(x)=120x-30x^2-16x^2+4x^3

V(x)=4x^3-46x^2+120x

Differentiate w.r.t x

V'(x)=12x^2-92x+120

V'(x)=0

12x^2-92x+120=0

3x^2-23x+30=0

3x^2-18x-5x+30=0

3x(x-6)-5(x-6)=0

(x-6)(3x-5)=0

x-6=0\implies x=6

3x-5=0\implies x=\frac{5}{3}

Again differentiate w.r.t x

V''(x)=24x-92

Substitute x=6

V''(6)=24(6)-92=52>0

Substitute x=5/3

V''(5/3)=24(5/3)-92=-52

Hence, the volume is maximum at x=\frac{5}{3}

Therefore, the side of the square ,x=\frac{5}{3} in cutout that gives the box the largest possible volume.

5 0
3 years ago
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