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bearhunter [10]
3 years ago
13

Solve this question and how to do it

Mathematics
2 answers:
katovenus [111]3 years ago
7 0

Answer:

Step-by-step explanation:

As the fractions are not like fraction, find LCM for 5 and 15

5 is a prime number and 15 is multiple of 5.So, LCM = 15

\dfrac{3}{5}=\dfrac{3*3}{5*3}=\dfrac{9}{15}\\\\\dfrac{7}{15}+\dfrac{3}{5}=\dfrac{7}{15}+\dfrac{9}{15}

           = \dfrac{7+9}{15}\\\\=\dfrac{16}{15}\\\\= 1\dfrac{1}{15}

satela [25.4K]3 years ago
6 0

Answer:

Step-by-step explanation:

7/15 + 3/5

I'd multiply 3/5 by 3 so that both of the denominators (bottom number) are the same.

Now all we have to do is add the Numerators tog

7/15 + 9/15ether (the top number)

7/15 +9/15 = 16/15 or 1 1/15

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3 0
3 years ago
What 2 numbers have the absolute given value of 4​
andrezito [222]

Answer:

-4 and 4

Step-by-step explanation:

An absolute value sign makes an answer positive regardless

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3 years ago
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How many solutions does 4(x-5)+2=4x—18 have??
baherus [9]
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4 0
3 years ago
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
3 years ago
Height of a parallelogram is half it's base.if it's area is 200 sq cm.find it's height and base.
Scilla [17]

Answer:

Step-by-step explanation:

4 0
3 years ago
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