Question

A: What is the perimeter of HOUSE?

Answer 1

First calculate distances or lengths(Refer to attachment)

A:-

$\\ \sf\longmapsto Perimeter=Sum\:of\:sides$

$\\ \sf\longmapsto 5.3+9+11+9+9.7$

$\\ \sf\longmapsto 15+29$

$\\ \sf\longmapsto 44$

B:-

Refer to the attchment

C:-

$\\ \sf\longmapsto \left(\dfrac{1+4}{2},\dfrac{1+6}{2}\right)$

$\\ \sf\longmapsto \left(\dfrac{5}{2},\dfrac{7}{2}\right)$

D:-

EH>OH

E:-

$\\ \sf\longmapsto Perimeter$

$\\ \sf\longmapsto 9.7+5.3+9$

$\\ \sf\longmapsto 24$

Answer 2

Answer:

The coordinates of the HOUSE:

• H(-7, 1), O(1, 6), U(4, 1), S(4, -8), E(-7, -8)

Part A

To find the perimeter first find the length of each side:

• OH = $\sqrt{(1 +7)^2+(6-1)^2} = \sqrt{64+25} =\sqrt{89}$ ≈ 9.43 units
• OU = $\sqrt{(4-1)^2+(1-6)^2} = \sqrt{9+25} = \sqrt{34}$ ≈ 5.83 units
• US = 1 - (-8) = 9 units
• SE = 4 - (-7) = 11 units
• EH = 1 - (-8) = 9 units

The perimeter is:

• P = 9.43 + 5.83 + 9 + 11 + 9 = 44.26 units

Part B

• OH = 9.43 units (see part A)

Part C

Use midpoint formula:

• x = (4 + 1)/2 = 2.5
• y = (1 + 6)/2 = 3.5

The point is (2.5, 3.5)

Part D

• OH = 9.43 units > EH = 9 units (see part A)

Part E

• P(ΔHOU) = OH + OU + HU (or SE) = 9.43 + 5.83 + 11 = 26.26 units