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3 years ago

Sarah has a 6 cup bag of rice. If a serving is ¾ of a cup, how many servings does Sarah have?

Mathematics

2 answers:

kondaur [170]3 years ago

5 0

Answer:

There are 8 servings

Step-by-step explanation:

6÷3/4= 8

DedPeter [7]3 years ago

4 0

Answer:

3/4+3/4+3/4+3/4+3/4+3/4=4.5

4.5+3/4+3/4=6

Answer is 8

Step-by-step explanation:

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I don’t get how to solve this

Annette [7]

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3 years ago

Someone pls help this is an emergency

harina [27]

Answer:

3,2 and -2

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3 years ago

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Serena uses chalk to draw a straight line on the sidewalk. The line is 12 ft long. She wants to divide the line into sections th

ElenaW [278]

<h3><u>Question:</u></h3>

Serena uses chalk to draw a straight line on the sidewalk. The line is 1/2 ft long. She wants to divide the line into sections that are each 1/8 ft long. How many sections will the line be divided into?

<h3><u>Answer:</u></h3>

The number of sections that the line is divided is 4

<h3><u>Solution:</u></h3>

Given that, Serena uses chalk to draw a straight line on the sidewalk

The line is 1/2 ft long. She wants to divide the line into sections that are each 1/8 ft long

From given,

$Total\ length\ of\ line = \frac{1}{2} \text{ feet }\\\\Length\ of\ each\ section = \frac{1}{8} \text{ feet }$

To find: Number of sections can be made

The number of sections that can be made is found by dividing the total length of line by length of each section

$\text{Number of sections } = \frac{\text{Total length of line}}{\text{length of each section}}$

Substituting the values, we get,

$\text{Number of sections } = \frac{\frac{1}{2}}{\frac{1}{8}}\\\\\text{Number of sections } = \frac{1}{2} \times \frac{8}{1}\\\\\text{Number of sections } = 4$

Thus number of sections that the line is divided is 4

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3 years ago

Whats 2+2 i dont know what it is

SOVA2 [1]

Answer:

Step-by-step explanation:

2+2=4

thanks:D

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3 years ago

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Please find the square roots of the following complex number.

Nana76 [90]

Hey there,

First, find the square root of the given equation.

$\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))$

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

$=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})$

Best of Luck!

6 0

3 years ago