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slava [35]
3 years ago
11

Simplify completely quantity 12 x plus 36 over quantity x squared minus 4 x minus 21 and find the restrictions on the variable..

Mathematics
2 answers:
Vesna [10]3 years ago
4 0
The answer is 12/x-7, x ≠ 7, x ≠ −3
Softa [21]3 years ago
3 0
To simplify the expression stated, it is better to write it in the numerical form. The statement is:

<span>quantity 12 x plus 36 over quantity x squared minus 4 x minus 21

The numerical form is:

12x+36 / (x</span>²-4x-21)

Simplifying,
12x+36 / (x<span>²-4x-21)
</span>12 (x+3) / (x+3)(x-7)

We can cancel the x+3 term, leaving only:
12/(x-<span>7)</span>
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Can (5z+3)(-5z-3) result in a difference of squares
castortr0y [4]

Answer:

no, it cannot

Step-by-step explanation:

a difference of square is: a² - b² = (a - b)(a + b)

looking at the expression (5z+3)(-5z-3), we see that it does not fit the criteria of the breakdown of a perfect square, as (-5z-3) has a negative <em>a</em> term (-5z)

if we FOILed (5z+3)(-5z-3) out, we would get:

-25z² - 30z - 9, which is not a difference of squares

8 0
3 years ago
Solve for x : ax+v=3(x-c)
never [62]

Answer:

x=\frac{3c+v}{a-3}

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

3 0
4 years ago
Read 2 more answers
Subtract the expression 5x-(-3x2+24)
VARVARA [1.3K]

Answer:

-90 is the answer

Step-by-step explanation:

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4 0
3 years ago
HELLLPPPP
xenn [34]

Answer:

Step-by-step explanation:

The output of a function is 3 less than 6 times the

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8 0
3 years ago
Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?
lbvjy [14]

Answer:

x = StartFraction negative

(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction

Step-by-step explanation:

0 = – 3x2 – 2x + 6

It can still be written as

– 3x2 – 2x + 6 =0

Quadratic formula=

-b+or-√b^2-4ac/2a

Where

a=-3

b=-2

c=6

x= -(-2)+ or-√(-2)^2-4(-3)(6)/2(-3)

x = StartFraction negative

(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction

8 0
3 years ago
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