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slava [35]
3 years ago
11

Simplify completely quantity 12 x plus 36 over quantity x squared minus 4 x minus 21 and find the restrictions on the variable..

Mathematics
2 answers:
Vesna [10]3 years ago
4 0
The answer is 12/x-7, x ≠ 7, x ≠ −3
Softa [21]3 years ago
3 0
To simplify the expression stated, it is better to write it in the numerical form. The statement is:

<span>quantity 12 x plus 36 over quantity x squared minus 4 x minus 21

The numerical form is:

12x+36 / (x</span>²-4x-21)

Simplifying,
12x+36 / (x<span>²-4x-21)
</span>12 (x+3) / (x+3)(x-7)

We can cancel the x+3 term, leaving only:
12/(x-<span>7)</span>
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if a quadratic equation with real coefficients has a discriminant of -36 then what type of roots does it have
Aleks04 [339]

Step-by-step explanation:

We have,

If a quadratic equation with real coefficients has a discriminant of -36.

The general form of quadratic equation is :

ax^2+bx+c=0

The discriminant of this equation is : D=b^2-4ac

If D=0, it will have 1 real roots

If D>0, it will have 2 real roots

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lesya692 [45]

Answer:

1. y = \frac{-A}{By}x + \frac{C}{By}

2. Divide the Opposite of A and B

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Step-by-step explanation:

1. Ax + By = C

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3 years ago
Combine the following expressions:
melisa1 [442]

ANSWER

(4n - 1)\sqrt{3 n} + 3\sqrt{n}

EXPLANATION

The given expression is

\sqrt{48 {n}^{3} }  +  \sqrt{9n}  -  \sqrt{3n}

We remove the perfect squares under the radical sign.

\sqrt{16 {n}^{2}  \times3 n}  +  \sqrt{9n}  -  \sqrt{3n}

We can now take square root of the perfect squares and simplify them further.

\sqrt{16 {n}^{2}}   \times \sqrt{3 n} +   \sqrt{9} \times  \sqrt{n}  -  \sqrt{3n}

This simplifies to:

4n\sqrt{3 n} + 3\sqrt{n}  -  \sqrt{3n}

This further simplifies to:

(4n - 1)\sqrt{3 n} + 3\sqrt{n}

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3 years ago
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