8 x 8 = 64
Each ‘face’ is 64in^2
64 x 6 = 384
= 384in^2
Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
The exterior angles of a polygon all add to 360, if you need to find an exterior angle when given the number of sides and that all angles are equal you simply do: 360/ number of sides.
When you need to find the exterior angle when given an interior angle, you do: 180- interior angle.
Hope this helps :)
A triangle can only have at most one right angle.
Here's a proof that shows why this is so:
We know that the sum of all interior angles of a triangle must add up to 180.
Let's say the interior angles are A, B, and C
A + B + C = 180
Let's show that having two right angles is impossible
Let A = B = 90
90 + 90 + C = 180
180 + C = 180
Subtract 180 from both sides
C = 0
We cannot have an angle with 0 degrees in a triangle. Thus, it is impossible to have 2 right angles in a triangle.
Let's try to show that it's impossible to have 3 right angles
Let A = B = C = 90
90 + 90 + 90 = 180 ?
270 ≠ 180
Thus it's impossible to have 3 right angles as well.
Let's show that is possible to have 1 right angle
Let A = 90
90 + B + C = 180
Subtract both sides by 90
B + C = 90
There are values of B and C that will make this true. Thus, a triangle can have at most one right angle.
Have an awesome day! :)
Answer:
5%
Step-by-step explanation:
487/9374=0.05
0.05 would translate to 5%
Hope this helps! :)
