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3 years ago

Estimate the sum of 672 and 830 by rounding to the nearest hundred before adding.

Mathematics

2 answers:

Nitella [24]3 years ago

4 0

Answer:

you round off to the nearest hundred which is 672 and 830 which I find to to 672 and 830 becomes 1000

kogti [31]3 years ago

3 0

Answer:

700 800

Step-by-step explanation:

672 is closer to 700 and 830 is closer to 800 lil tip 5 or more let it soar four or less let it rest

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The radius of a circle is 9cm what is the length of its diameter?

Kobotan [32]

The answer would be 18cm

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3 years ago

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Just number 2 please i’ve tried many times... i need an equation and the answer :)

Triss [41]

Keller collected $62.48 and Izzy collected $47.83 and J collected $19.98

Step-by-step explanation:

Step 1; Assume that J collected $x, Keller collected $y and Izzy collected $z. All three combined collected $125.95, so

x + y + z = 125.95, take this as equation 1.

From the given data, the following equations can be formed.

y = 42.50 + x or x = y - 42.50 take this as equation 2 and

y = 15 + z, take this as equation 3.

Step 2; Now we must determine x and y in terms of z, so that equation 1 can be solved (the equations can be in terms of any term x, y or z.)

Rearranging equation 2 and 3,

we get 15 + z so x = y - 42.50, y = x = 15 + z - 42.50, take this as equation 4,

If we substitute equations 4, 2 in 1, we get

(15 + z - 42.50) + (15 + z) + z = 125.95,

3z - 12.5 = 129.95,

3z = 142.45, so z = 47.833.

Substitute z = 47.833 in equation 3.

y = 15 + 47.8333 = 62.4833.

Substitute y = 62.4833 in equation 2,

x = 62.4833 - 42.50 = 19.9833.

Rounding of the values of x,y, and z to nearest hundredth we get

x = $19.98, y = $62.48 and z = $47.48.

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3 years ago

What is the percent of 19 and 5

Alexandra [31]

I think the answer should be 24

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2 years ago

the admission fee for a charity event is 7 dollars for children and 10 dollars for adults the event was attended by 700 people a

ollegr [7]

Given:
$7/child
$10/adult
Total people = 700
Total money = $6,400

First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people

1. a+c = 700
2. 10a+7c = 6,400

Then, rearrange the equation to solve for a variable.
c = 700-a

Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
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9a+700-700 = 6400-700
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700-633 $\frac{1}{3}$ = c = 66 $\frac{2}{3}$ = # of children attended

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3 years ago