$\sqrt{(125^2)^{-\frac{1}{3}}}\qquad\text{use}\ (a^n)^m=(a^m)^n\\\\=\sqrt{\left(125^{-\frac{1}{3}\right)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=125^{-\frac{1}{3}}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{1}{125^\frac{1}{3}}\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\dfrac{1}{\sqrt[3]{125}}=\dfrac{1}{5}\qquad\text{because}\ 5^3=125$

5 0

3 years ago

Yeooo guys please help me :) !

Afina-wow [57]

The answer is $138.98 Dollars

6 0

3 years ago

Calculate 20% of R400

Zinaida [17]

Answer:

Step-by-step explanation:

400: 100 you find 1% you multiply it by 20 and you have 20%

400 : 100 * 20 =

4 * 20 =

6 0

2 years ago

The sides of a rectangle are 3t - 2 and 5t + 7. Write an expression for the perimeter of the rectangle.

natka813 [3]

How does this have anything to do with factoring?
Perimeter of the rectangle would just be 2(3t-2)+2(5t+7)
Simplify that to get 6t-4+10t+14, then 16t+10

6 0

3 years ago

Y=x(2)-2x-3 find the value of x when y=1​

Y=x(2)-2x-3 find the value of x when y=1