Step-by-step explanation:
<em>option</em><em> </em><em>D </em><em>is </em><em>correct</em><em>,</em>
<em>because</em><em> </em><em>the </em><em>orientation</em><em>/</em><em>postion</em><em> </em><em>of </em><em>the </em><em>vertices </em><em>does </em><em>got </em><em>changed.</em><em>.</em><em>.</em>
<em>that's</em><em> </em><em>why </em><em>it </em><em>is </em><em>not </em><em>true</em>
<em>hope </em><em>this </em><em>answer </em><em>helps </em><em>you </em><em>dear </em><em>take</em><em> </em><em>care</em>
Ingles C would be diagonal so your best answer be D hope this helped !!!!!!
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
The total land area of the world is about fifty-seven million, two hundred eighty thousand square miles is 57, 280, 000 square miles
<em><u>Solution:</u></em>
Given that, we have to write the given words in number
The total land area of the world is about fifty-seven million, two hundred eighty thousand square miles
The number of zeros in million is 6
Here given that 57 million
So, 57 million means 57, followed by 6 digits
two hundred eighty thousand means 280 followed by 3 zeros
two hundred eighty thousand = 280 thousand
Thus the number is: 57, 280, 000
I think the answer is decay