8

Mathematics

1 answer:

Nata [24]2 years ago

6 0

Answer: 15, -8

Step-by-step explanation:

$u_2=7\\u_2=u_1+r\\u_3=u_1+2r\\u_4=u_1+3r\\\\u_1+u_2+u_3+u_4=4u_1+6r=12\\u_1+r=7\\\\$

$\left \{ \begin {array} {ccc|c|c}u_1+r&=&7&-4&-6\\4u_1+6r&=&12&1&1\\\end {array} \right.\\\\\\\left \{ \begin {array} {ccc}2r&=&-16\\-2u_1&=&-30\\\end {array} \right.\\\\\\\left \{ \begin {array} {ccc}r&=&-8\\u_1&=&15\\\end {array} \right.\\\\\\Proof:\\u_1=15\\u_2=7\\u_3=-1\\u_4=-9\\sum=12\\$

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Consider the diagram shown and answer the following questions; the radius of this circle is 6 inches:

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Refer to the figure shown below.

Part 1
Triangles VPU and SPU are congruent because of SSA. Therefore,
∠TUV = ∠TUS = 39°.
Because angles in quadrilateral PVUS sum to 360°, therefore
The Central ∠VPS = 360 -(90+39+39+90) = 102°.
The measure of arc VTS = ∠VPS = 102°.

Part 2
We know that line segments PO = PS = PT = 6 in (radius).
Because TO is a diameter, ∠TMO = 90°.
From the indicated right triangles ΔUPV, ΔUPS, ΔMOT, we can calculate the lengths of PU, US, UV, MT and MO.

Part 3
Angles in a triangle sum to 90°. Because ∠MOP = 49°, therefore
∠MTO = 90 - 49 = 41°.
∠VPU = ∠SPU = 90 - 39 = 51°.