Answer:
531.4
Step-by-step explanation:
ED/AE=BC/AB
ED=AE*BC/AB
ED=240*620/280
ED=531.4
One cat has four paws, so there are 120/4=30 cats. If a "set" of cats is two uncool cats and three cool cats, there are five cats in a set, so there are 30/5=6 sets. Since each of the six sets contains three cool cats, there are 18 cool cats in the family.
28.7083333333...
But you could also round it up to 29.
So basically to estimate your answer, you must
Y = 1.3x
point C : (3,?)...so we sub in 3 for x and solve for y
y = 1.3(3)
y = 3.9
so point C is (3,3.9)
point D : (-6,?)...so we sub in -6 for x and solve for y
y = 1.3(-6)
y = -7.8
so point D is (-6,-7.8)
