Graph the function y=3/4sin1/2x

Help! Need this done quickly! picture is upside down so please flip your screen! sorry!

iogann1982 [59]

Answer:

x=6

Step-by-step explanation:

Hi there!

1) Determine the perimeter of the square

We're given that the perimeters of the square and the rectangle are equal. Therefore, after finding the perimeter of the square, we will also know the perimeter of the rectangle.

Find the side length of the square using the area formula:

$A=l^2$ where l is the side length

Plug in the given area 121 in.²

$121=l^2$

Take the square root of both sides

$\sqrt{121} = \sqrt{l^2} \\11=l$

Therefore, the side length of the square is 11 inches. Plug this into the perimeter formula:

$P=4l$ where l is the side length

$P=4(11)\\P=44$

Therefore, the perimeter of the square is 44 inches. The perimeter of the rectangle is also 44 inches.

2) Determine the value of x

Use the formula for the perimeter of a rectangle:

$P=2(l+w)$ where l is the length and w is the width

Plug in 3x and x-2 as the length and width

$P=2(3x+(x-2))\\P=2(3x+x-2)\\P=2(4x-2)$

Plug in the perimeter 44 in.

$44=2(4x-2)$

Expand the parentheses

$44=8x-4$

Add 4 to both sides to isolate 8x

$44+4=8x-4+4\\48=8x$

Divide both sides by 8 to isolate x

$\frac{48}{8}=\frac{8x}{8} \\6=x$

Therefore, the value of x is 6.

I hope this helps!

4 0

2 years ago

Solve the following congruence equations for X a) 8x = 1(mod 13) b) 8x = 4(mod 13) c) 99x = 5(mod 13)

xxMikexx [17]

Answer:

a) 5+13k where k is integer

b) 20+13k where k is integer

c)12+13k where k is integer

Step-by-step explanation:

(a)

$8x \equiv 1 (mod 13) \text{ means } 8x-1=13k$ .

8x-1=13k

Subtract 13k on both sides:

8x-13k-1=0

Add 1 on both sides:

8x-13k=1

I'm going to use Euclidean Algorithm.

13=8(1)+5

8=5(1)+3

5=3(1)+2

3=2(1)+1

Now backwards through the equations:

3-2=1

3-(5-3)=1

3-5+3=1

(8-5)-5+(8-5)=1

2(8)-3(5)=1

2(8)-3(13-8)=1

5(8)-3(13)=1

So compare this to:

8x-13k=1

We see that x is 5 while k is 3.

Anyways 5 is a solution or 5+13k is a solution where k is an integer.

b)

$8x \equiv 4 (mod 13)$

8x-4=13k

Subtract 13k on both sides:

8x-13k-4=0

Add 4 on both sides:

8x-13k=4

We got this from above:

5(8)-3(13)=1

If we multiply both sides by 4 we get:

8(20)-13(12)=4

So x=20 and 20+13k is also a solution where k is an integer.

c)

[tex]99x \equiv 5 (mod 13)[/tex

99x-5=13k

Subtract 13k on both sides:

99x-13k-5=0

Add 5 on both sides:

99x-13k=5

Using Euclidean Algorithm:

99=13(7)+8

13=8(1)+5

Go back through the equations:

13-8=5

13-(99-13(7))=5

8(13)-99=5

99(-1)+8(13)=5

Compare this to 99x-13k=5 and see that x=-1 or -1+13=12 or 12+13k is a solution where k is an integer.

8 0

2 years ago

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STOP AND HELP ME PLZZZZZ

Stella [2.4K]

Answer:

#12 is 1

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The University of Montana ski team has thirteen entrants in a men's downhill ski event. The coach would like the first, second,

sleet_krkn [62]

Answer:

1716 ways

Step-by-step explanation:

Given that :

Number of entrants = 13

The number of ways of attaining first, second and third position :

The number of ways of attaining first ; only 1 person can be first ;

Using permutation :

nPr = n! ÷(n-r)!

13P1 = 13! ÷ 12! = 13

Second position :

We have 12 entrants left :

nPr = n! ÷(n-r)!

12P1 = 12! ÷ 11! = 12

Third position :

We have 11 entrants left :

nPr = n! ÷(n-r)!

11P1 = 11! ÷ 10! = 11

Hence, Number of ways = (13 * 12 * 11) = 1716 ways

8 0

2 years ago

What substitution should be used to rewrite 4x^4-21x^2+20=0 as a quadratic equation

Andreyy89

let y = x^2

4y^2 -21y + 20 = 0

solve for y

then substitute back in to get x

8 0

3 years ago

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