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makkiz [27]
2 years ago
8

What is the image of (-4,8) after a dilation by a scale factor of 2 centered at the origin?

Mathematics
1 answer:
Gala2k [10]2 years ago
8 0
The answer is (-8, 16)

a scale factor of 2 will enlarge the image. all you need to do is multiply the x and y by 2.
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Please help me on this problem !
Rashid [163]

Answer:

x = 5 , y = 5\sqrt{3}

Step-by-step explanation:

Using the sine and cosine ratios in the right triangle and exact values.

sin30° = \frac{1}{2} , cos30° = \frac{\sqrt{3} }{2} , then

sin30°= \frac{opposite}{hypotenuse} = \frac{x}{10} = \frac{1}{2} ( cross- multiply )

2x = 10 ( divide both sides by 2 )

x = 5

and

cos30° = \frac{adjacent}{hypotenuse} = \frac{y}{10} = \frac{\sqrt{3} }{2} ( cross- multiply )

2y = 10\sqrt{3} ( divide both sides by 2 )

y = 5\sqrt{3}

8 0
2 years ago
What is equal to 2/3
vovangra [49]


Some fractions that are equal to 2/3 are: 4/6 and 6/9

(You just have to multiply the numerator and denominator by the same number.)

Decimal: 0.666...

(Divide the numerator by the denominator.)

Percent: 66.6%

(Multiply the decimal by 100.)

<em>Hope it helps</em> :)

6 0
3 years ago
Read 2 more answers
6 minus 4 2/7 =<br> ANSWER ASAP AND BE RIGHT<br> EXPLAINNNN STEP BY STEP<br> TO BE BRAINLIEST
faust18 [17]

Answer:

12/7

Step-by-step explanation:

6-4 2/7 =

42/7 - 30/7 =

12/7

6 0
3 years ago
Which function represents the graph of h(x)=2|x+3|−1 after it is translated 2 units right?
harina [27]

\bf ~\hspace{10em}\textit{function transformations} \\\\\\ \begin{array}{llll} f(x)= A( Bx+ C)^2+ D \\\\ f(x)= A\sqrt{ Bx+ C}+ D \\\\ f(x)= A(\mathbb{R})^{ Bx+ C}+ D \end{array}\qquad \qquad \begin{array}{llll} f(x)=\cfrac{1}{A(Bx+C)}+D \\\\\\ f(x)= A sin\left( B x+ C \right)+ D \end{array} \\\\[-0.35em] ~\dotfill\\\\ \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\ \bullet \textit{ flips it upside-down if } A\textit{ is negative}

\bf ~~~~~~\textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if } B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis} \\\\ \bullet \textit{ horizontal shift by }\frac{ C}{ B}\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}

\bf ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by } D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{ B}

now with that template in mind

\bf h(x)=\stackrel{A}{2}|\stackrel{B}{1}x+\stackrel{C}{3}|\stackrel{D}{-1}\qquad \qquad \stackrel{\textit{C=C-2 a translation to the right}}{h(x)=2|x\boxed{+3-2}|-1} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill h(x)=2|x+1|-1~\hfill

8 0
3 years ago
Read 2 more answers
​3x-2≤5(x+2) . show all steps please.
Natasha_Volkova [10]

Answer:

-6 ≤x

Step-by-step explanation:

3x-2≤5(x+2)

Distribute

3x-2≤5x+10

Subtract 3x

3x-2-3x≤5x +10-3x  

-2 ≤2x+10

Subtract 10 from each side

-2-10 ≤2x+10-10

-12 ≤2x

Divide by 2

-12/2≤2x/2

-6 ≤x

3 0
3 years ago
Read 2 more answers
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