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3 years ago

How to do long division with polynomials?

1 answer:

5 0

Divide the first term of the numerator by the first term of the denominator, and put that in the answer.Multiply the denominator by that answer, put that below the numerator.Subtract to create a new polynomial.

Hope this helps. :)

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I need to find the derivative of this equation

I am Lyosha [343]

This is the answer
if u do 3rd, 4th .... derivatives the answer will be 0 again.

6 0

3 years ago

Write the place of each underline digit. 164.13 -

tino4ka555 [31]

Answer: 1 It's the hundreds place

Step-by-step explanation:

164.13

1 is hundreds 6 is tens 4 is one .(point) 1 is uniths and 3 is tenths

Anything after the decimal ends in (ths) (ones(uniths), tenths, hundreths) but since we only have to write

The underlined digit which is 1 it's only HUNDREDS or the hundreds place value

3 0

2 years ago

The figure is made up of a hemisphere and a cylinder. What is the volume of the figure?

jeka94

890.11753 m^3. get the volume of a hemisphere then add that to the volume of a cylinder.

7 0

2 years ago

Help please this is for my homework that is due to tomorrow!!

Murljashka [212]

The given polygons are similar

Step-by-step explanation:

By observing the given diagrams, we can see that the respective angles are congruent.

Two shapes are said to be similar if they have same shapes or one shape is created by uniformly increasing or decreasing the side of other.

For this purpose we find the scale factor of greater to smaller image, if the scale factor is same for each side then the two shapes are similar

So,

The scale factor is:

$\frac{EF}{AB} = \frac{3}{1} = 3\\\\\frac{FG}{BC} = \frac{9}{3} = 3\\\\\frac{GH}{CD} = \frac{15}{5} = 3\\\\\frac{EH}{AD} = \frac{21}{7} = 3$

We can see that the scale factor is same for all sides.

Hence,

The given polygons are similar

Keywords: Polygons, similarity

Learn more about polygons at:

#LearnwithBrainly

5 0

2 years ago

3 determine the highest real root of f (x) = x3− 6x2 + 11x − 6.1: (a) graphically. (b) using the newton-raphson method (three it

Juliette [100K]

(a) See the first attachment for a graph. This graphing calculator displays roots to 3 decimal places. (The third attachment shows a different graphing calculator and 10 significant digits.)

(b) In the table of the first attachment, the column headed by g(x) gives iterations of Newton's Method. (For Newton's method, it is convenient to let the calculator's derivative function compute the derivative f'(x) of the function f(x). We have defined g(x) = x - f(x)/f'(x).) The result of the 3rd iteration is ...

... x ≈ 3.0473167

(c) The function h(x₁, x₂) computes iterations using the secant method. The results for three iterations of that method are shown below the table in the attachment. The result of the 3rd iteration is ...

... x ≈ 3.2291234

(d) The function h(x, x+0.01) computes the modified secant method as required by the problem statement. The result of the 3rd iteration is ...

... x ≈ 3.0477377

(e) Using Mathematica, the roots are found to be as shown in the second attachment. The highest root is about ...

... x ≈ 3.0466805180

_____

Comment on these methods

Newton's method can have convergence problems if the starting point is not sufficiently close to the root. A graphing calculator that gives a 3-digit approximation (or better) can help avoid this issue. For the calculator used here, the output of "g(x)" is computed even as the input is typed, so one can simply copy the function output to the input to get a 12-significant digit approximation of the root as fast as you can type it.

The "modified" secant method is a variation of the secant method that does not require two values of the function to start with. Instead, it uses a value of x that is "close" to the one given. For our purpose here, we can use the same h(x1, x2) for both methods, with a different x2 for the modified method.

We have defined h(x1, x2) = x1 - f(x1)(f(x1)-f(x2))/(x1 -x2).

6 0

2 years ago