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Andrei [34K]
3 years ago
12

How to do long division with polynomials?

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0
<span>Divide the first term of the numerator by the first term of the denominator, and put that in the answer.Multiply the denominator by that answer, put that below the numerator.Subtract to create a new polynomial.

Hope this helps. :)

</span>
You might be interested in
Four ninths minus four tenths equals blank ?
melisa1 [442]

Answer:

\frac{4}{90}

5 0
3 years ago
Read 2 more answers
Please help!! Will give brainliest! Giving lots of points!
olga nikolaevna [1]

Answer:

d) (9*3/4)+y

Step-by-step explanation:

b) 9+y*(3/4)

This expression is not equivalent, as the original expression, y+9*\frac{3}{4} , has 9 multiplied to \frac{3}{4} instead of y. You can interchange values like this when it comes to addition, but not multiplication.

c) (y+9)(3/4)

This expression is also not equivalent. After opening up the parentheses, it would again result in y being multiplied to \frac{3}{4}.

(y+9)(3/4)\\= y(3/4)+9(3/4)

d) (9*3/4)+y

This expression is equivalent, as 9 and \frac{3}{4} are still being multiplied together and y is added to the product. We can actually rearrange this to look like the original expression:

(9*3/4)+y\\=y+(9*3/4)\\=y+(9*\frac{3}{4} )\\=y+9*\frac{3}{4}

I hope this helps!

3 0
3 years ago
Hello again everyone, need help on this Division question pls (:
scoundrel [369]
321.125 is your answer
6 0
3 years ago
2.(a+bc)+cb+ab+ac-3.(ab-cb-ba+bc)
SVETLANKA909090 [29]
2(a+bc)=2a+2bc
3.(ab-cb-ba+bc)= 3ab-3cb-3ba+3bc
Since the brackets and multiplication have a higher order than the rest.

Cb=Bc
Ab=ba
Ac=Ca

Because multiplication is commutative.

2a+2bc + cb +ab + ac -(3ab-3cb-3ba+3bc)

2a + 2bc + cb + ab + ac(+ -3ab - - 3cb - -3ba +-3bc)

2a + 2bc + cb + ab + ac -3ab + 3cb + 3ba -3bc

2a + (2bc-3bc +cb + 3cb ) + (ab -3ab + 3ba) + ac

=2a + 3cb + ba+ ac OR 2a +3bc + ab + ac



The Or is just a different way to write it.

Hope this helps
4 0
3 years ago
Please include work
OLga [1]

Answer:

9.     6k + 5 and 2k - 1.

10.    5√2 .

Step-by-step explanation:

9.    Area = 12k^2 + 4k - 5

Factoring:

12k^2 - 6k + 10k - 5

= 6k(2k - 1) + 5(2k - 1)

= (6k + 5)(2k - 1)

So the required lengths are 6k + 5 and 2k - 1.

10.  The ratio of a leg to the hypotenuse is  1: √2 so if the hypotenus = 10 the length of a leg is 10 / √2  

= 10 √2  / 2

= 5√2 .

7 0
3 years ago
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