Question

For the polynomial 6xy2 – 5x2y? + 9x2 to be a trinomial with a degree of 3 after it has been fully simplified, the missing exponent of the y-term must be

Answer 1

Consider the polynomial $6xy^2-5x^2y^?+9x^2$.

For this polynomial to be trinomial with a degree of 3. We have to identify the missing exponent of the 'y' term.

Let the missing exponent of the 'y' term be 0

So, the polynomial will be $6xy^2-5x^2y^0+9x^2$

= $6xy^2-5x^2+9x^2$

= $6xy^2+4x^2$ which is not a trinomial, which is a binomial.

So, the missing exponent of 'y' can'not be zero.

Let the missing exponent of the 'y' term be 2

So, the polynomial will be $6xy^2-5x^2y^2+9x^2$

= $6xy^2-5x^2y^2+9x^2$

= $6xy^2-5x^2y^2+9x^2$ which is a trinomial of degree 4.

So, the missing exponent of 'y' can'not be '2'.

If we will take the missing exponent of 'y' more than 2, than the degree of the given polynomial will not be 3 anymore.

Let the missing exponent of the 'y' term be 1

So, the polynomial will be $6xy^2-5x^2y^1+9x^2$

= $6xy^2-5x^2y+9x^2$

= $6xy^2+4x^2$ which is a trinomial of degree 3

So, the missing exponent of 'y' is 1.

Answer 2

I don't know how to solve this, but I found the answer somehow. Its 1... sorry.