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3 years ago

PLS HELP ITS URGENT

Mathematics

1 answer:

vfiekz [6]3 years ago

7 0

Answer:

Surface area=48 in^2

See the image for solution

You might be interested in

Which of the following descriptions represents the transformation shown in the image

Viktor [21]

Answer: A. 270° rotation, 3 units left, and 2 units up

Step-by-step explanation:

C = (1, 1) D = (3, 3) E = (2, -2)

270° rotation counterclockwise means (x, y) = (y, -x)

new C = (1, -1) new D = (3, -3) new E = (-2, -2)

3 units left means subtract 3 from the x-coordinate

newer C =( -2, -1) newer D = (0, -3) newer E = (-5, -2)

2 units up means add 2 to the y-coordinate

C' = (-2, 1) D' = (0, -1) E' = (-5, 0)

Since the first option worked, there is no need to check the other options.

7 0

3 years ago

Read 2 more answers

What does x equal? Plz hurry. First to answer correctly will be marked brainliest ASAP.

svet-max [94.6K]

Answer:

6.0

Step-by-step explanation:

This involves using SOH CAH TOA.

we use Sin as we want to find x (which is side O, and we are given H).

So we get sin37 = O/H

= x/10

so x = 10 sin 37 = 6.018... = 6.0 to the nearest tenth.

3 0

3 years ago

HELP PLEASE and show work

larisa86 [58]

Answer:

$\boxed{\stackrel{\Large\frown}{PQS}\:= 222°}$

Explanation:

Since $\overline{PR}$ is a diameter, arc $\stackrel{\Large\frown}{PQR}\:= 180°.$

Given that $\angle{SUR} = 42°$ is a subtended central angle by two diameters,

$\stackrel{\large\frown}{RS} \:= 42°$ .

Using the rule of arcs, $\stackrel{\Large\frown}{PQR} + \stackrel{\large\frown}{RS} \: = \: \stackrel{\Large\frown}{PQS}$ →

$180° + \: 42° = \: \stackrel{\Large\frown}{PQS}$

$222° = \: \stackrel{\Large\frown}{PQS}$

$\stackrel{\Large\frown}{PQS} \: = \: 222°$

3 0

3 years ago

In the figure BD||EG and the measure of angleACB=35 degree. What is the measure of angle GFH

GREYUIT [131]

That would also be 35

8 0

3 years ago

Read 2 more answers

Need help with the blanks

Crazy boy [7]

Answers:
33. Angle R is 68 degrees
35. The fraction 21/2 or the decimal 10.5
36. Triangle ACG
37. Segment AB
38. The values are x = 6; y = 2
40. The value of x is x = 29
41. C) 108 degrees
42. The value of x is x = 70
43. The segment WY is 24 units long
------------------------------------------------------
Work Shown:
Problem 33)
RS = ST, means that the vertex angle is at angle S
Angle S = 44
Angle R = x, angle T = x are the base angles
R+S+T = 180
x+44+x = 180
2x+44 = 180
2x+44-44 = 180-44
2x = 136
2x/2 = 136/2
x = 68
So angle R is 68 degrees
-----------------
Problem 35)
Angle A = angle H
Angle B = angle I
Angle C = angle J
A = 97
B = 4x+4
C = J = 37
A+B+C = 180
97+4x+4+37 = 180
4x+138 = 180
4x+138-138 = 180-138
4x = 42
4x/4 = 42/4
x = 21/2
x = 10.5
-----------------
Problem 36)
GD is the median of triangle ACG. It stretches from the vertex G to point D. Point D is the midpoint of segment AC
-----------------
Problem 37)
Segment AB is an altitude of triangle ACG. It is perpendicular to line CG (extend out segment CG) and it goes through vertex A.
-----------------
Problem 38)
triangle LMN = triangle PQR
LM = PQ
MN = QR
LN = PR
Since LM = PQ, we can say 2x+3 = 5x-15. Let's solve for x
2x+3 = 5x-15
2x-5x = -15-3
-3x = -18
x = -18/(-3)
x = 6
Similarly, MN = QR, so 9 = 3y+3
Solve for y
9 = 3y+3
3y+3 = 9
3y+3-3 = 9-3
3y = 6
3y/3 = 6/3
y = 2
-----------------
Problem 40)
The remote interior angles (2x and 21) add up to the exterior angle (3x-8)
2x+21 = 3x-8
2x-3x = -8-21
-x = -29
x = 29
-----------------
Problem 41)
For any quadrilateral, the four angles always add to 360 degrees
J+K+L+M = 360
3x+45+2x+45 = 360
5x+90 = 360
5x+90-90 = 360-90
5x = 270
5x/5 = 270/5
x = 54
Use this to find L
L = 2x
L = 2*54
L = 108
-----------------
Problem 42)
The adjacent or consecutive angles are supplementary. They add to 180 degrees
K+N = 180
2x+40 = 180
2x+40-40 = 180-40
2x = 140
2x/2 = 140/2
x = 70
-----------------
Problem 43)
All sides of the rhombus are congruent, so WX = WZ.
Triangle WPZ is a right triangle (right angle at point P).
Use the pythagorean theorem to find PW
a^2+b^2 = c^2
(PW)^2+(PZ)^2 = (WZ)^2
(PW)^2+256 = 400
(PW)^2+256-256 = 400-256
(PW)^2 = 144
PW = sqrt(144)
PW = 12
WY = 2*PW
WY = 2*12
WY = 24

3 0

3 years ago