2 years ago

Help please. ALGEBRA.

1 answer:

3 0

The answer is 100% 4x+4

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ira [324]

$\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}$

If $x\neq-2$ , then we can immediately cancel the factors of $x+2$ :

$\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}$

Factorize the numerator and denominator:

$x^2-x=x(x-1)$

$x^2+2x-3=(x+3)(x-1)$

Next, if $x\neq1$ , then

$\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}$

8 0

3 years ago

GenaCL600 [577]

Answer:

Step-by-step explanation:

A complementary angle is an angle at 90 degrees and is formed by 2 angles.

3 0

3 years ago

Reil [10]

Answer:

Step-by-step explanation:

3 0

2 years ago

disa [49]

The answer is 11/15 A

8 0

2 years ago

Amanda [17]

U should either multiply 8% by 16ml hope i helped. :)

8 0

3 years ago