AVERAGE between 90 and 100%
means not including 90 and 100% but not including 90 or 100%
average=(sum of values in set)/(how many values in the set)
so
4 exams, so there are 4 values
average=(sum)/4
the sum is the known+unknwon
sum=76+99+86+x
so
90<span><</span>average and average <span><</span>100
or
90<span><</span>average<span><</span>100
lets say average=a
a=sum/number
a=(76+99+86+x)/4
90<(76+99+86+x)/4<100
90<(76+99+86+x)/4 and (76+99+86+x)/4<100
solve each for x and find intersection
90<span><</span>(76+99+86+x)/4
times 4 both sides
360<span><</span>261+x
minus 261 both sides
99<span><</span>x
(76+99+86+x)/4<u><</u>100
times 4 both sides
261+x<u><</u>400
minus 261 both sides
x<u><</u>139
so
99<u><</u>x<u><</u>139
since max score is 100
99<u><</u>x<u><</u>100
interval notaion is
[99,100]
answer is 2nd one
Answer: you subtract the angles by the one you are trying to solve
Step-by-step explanation: learned about it in 6th grade
<u>Step by step explanation:</u>
Step 1:
Step 2:
Step 3:
Step 4:
Step 6:
Answer:
the number of cakes sell is 5
Step-by-step explanation:
The computation of the number of cakes sold is shown below;
Let us assume
The cake be C
And, the pie cost be P
Given that
There is two types of baked goods sold
The cost of the cake is $4
And, the cost of the pie cost is $64
Now the store sold 9 baked goods for a total of $44
So, the equation would be
C + P = 9
P = 9 - C ...... (1)
4C + 6P = 44............(2)
Now put the value of P in equation 2
4C + 6(9 - C) = 44
4C + 54 - 6C = 44
-2C = -10
C = 5
And, P = 4
hence, the number of cakes sell is 5
So first find a common denominator which is 100 in this question. Then change 5/10 into a denominator of 100 which is 50/100 you don't have to change 9/100 because it has a denominator of 100. So then add the fractions and the answer is 59/100
