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2 years ago

Covert 298.4 to a fraction

Mathematics

2 answers:

Kruka [31]2 years ago

7 0

$\\ \sf\longmapsto 298.4$

$\\ \sf\longmapsto \dfrac{2984}{10}$

$\\ \sf\longmapsto \dfrac{1492}{5}$

faltersainse [42]2 years ago

7 0

298.4/1 × 10/10

=2984/10

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half way through a bus 23 students have been dropped off and 48 students remain on the bus write an equation to Whether their ar

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Answer: 71 - 23 = 48

Step-by-step explanation: If you subtract 71 from 23 it will equal to 48 and there are 48 students on the bus still.

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3 years ago

Find the exact value. sin135°

Soloha48 [4]

Answer:

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Step-by-step explanation:

Note that

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3 years ago

5 is what percentage of 10 question: now do I divide 5 divided by 10 equals 0.5 then do I multiply 0.5 by 100 or divide 0.5 by 1

lara31 [8.8K]

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50%

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5 question is what percentage of 10 question

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0.5 × 100

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2 years ago

Is the quotient of 3/5 ÷ 6/7 greater than or less than 3/5? Explain

Vikki [24]

The quotient of two fraction is the multiplication between the first and the inverse of the second:

$\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \cdot \dfrac{d}{c}$

So, in your case, you have

$\dfrac{3}{5} \div \dfrac{6}{7} = \dfrac{3}{5} \cdot \dfrac{7}{6} = \dfrac{7}{10}$

So, the question now is: which is larger, 7/10 or 3/5? To answer this question, transform the second fraction so that it will have denominator 10 as well:

$\dfrac{3}{5} = \dfrac{3\cdot 2}{5 \cdot 2} = \dfrac{6}{10}$

So, now it is clear that

$\dfrac{7}{10} > \dfrac{6}{10}$

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3 years ago

Read 2 more answers

The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad

Leya [2.2K]

<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. $Q_1$ = 14

Median or second quartile i.e. $Q_2$ = 18

Third quartile or upper quartile i.e. $Q_3$ =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. $Q_1$ = 26

Median or second quartile i.e. $Q_2$ = 30

Third quartile or upper quartile i.e. $Q_3$ = 34

and maximum value = 38

The overlap of the two sets of data is as follows.

The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
And the maximum value of seventh grade is same as the lower quartile of eighth grade.

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. $Q_3-Q_1$

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

$8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5$

Hence, the number is : 1.5

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3 years ago