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sergeinik [125]
3 years ago
9

Verify that the points are the vertices of a parallelogram and find its area. (2,-1,1), (5, 1,4), (0,1,1), (3,3,4)

Mathematics
1 answer:
Gelneren [198K]3 years ago
6 0

Answer:

Area = 13.15 square units

Step-by-step explanation:

Let the given vertices be represented as follows:

A(2, -1, 1) = 2i - j + k

B(5, 1, 4) = 5i + j + 4k

C(0, 1, 1) = 0i + j + k

D(3, 3, 4) = 3i + 3j + 4k

(i) Let's calculate the vectors of all the sides:

\\AB = B - A =  (5i + j + 4k) - (2i - j + k)

AB = 5i + j + 4k - 2i + j - k                 [Collect like terms]

AB = 3i + 2j + 3k

BC = C - B =  (0i + j + k) - (5i + j + 4k)

BC = 0i + j + k - 5i - j - 4k                 [Collect like terms]

BC = -5i + 0j - 3k

CD = D - C =  (3i + 3j + 4k) - (0i + j + k)

CD = 3i + 3j + 4k - 0i - j - k                [Collect like terms]

CD = 3i + 2j + 3k

DA = A - D =  (2i - j + k) - (3i + 3j + 4k)

DA = 2i - j + k - 3i - 3j - 4k                [Collect like terms]

DA = -i - 4j - 3k

AC = C - A =  (0i + j + k) - (2i - j + k)

AC = 0i + j + k - 2i + j - k                [Collect like terms]

AC = -2i + 2j

BD = D - B = (3i + 3j + 4k) - (5i + j + 4k)

BD = 3i + 3j + 4k - 5i - j - 4k                [Collect like terms]

BD = -2i + 2j

(ii) From the results in (i) above, we can deduce that;

AB = CD This implies that AB || CD  [AB is parallel to CD]

AC = BD This implies that AC || BD  [AC is parallel to BD]

(iii) Therefore, ABDC is a parallelogram since opposite sides (AB and CD) are parallel. Hence, the points are vertices of a parallelogram

<u>Now let's calculate the area</u>

To find the area of the parallelogram, we find the magnitude of the cross product of any two adjacent sides.

In this case, we'll choose AB and AC

Area = |AB X AC|

Where;

AB X AC = \left[\begin{array}{ccc}i&j&k\\3&2&3\\-2&2&0\end{array}\right]

<u></u>

AB X AC = i(0 - 6) - j(0 + 6) + k(6 + 4)

AB X AC = - 6i - 6j + 10k

|AB X AC| = \sqrt{(-6)^2 + (-6)^2 + (10)^2}

|AB X AC| = \sqrt{172}

|AB X AC| = 13.15

Area = 13.15 square units.

<u></u>

<u></u>

<u>PS: </u> ACBD is also a parallelogram. The diagram has also been attached to this response.

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Which table shows a proportional relationship between weight and price?
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Answer:

second table (see the attached figure)

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form y/x=k or y=kx

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<u><em>Verify each table</em></u>

<em>First table </em>

Let

x ----> the weight in lb

y ----> the price in dollars

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k=y/x ----> k=3.5\1.5=2.33

For x=2, y=7

k=y/x ----> k=7/2=3.5

The values of k are different

therefore

This table not represent a  proportional relationship between weight and price

<em>Second table </em>

Let

x ----> the weight in g

y ----> the price in dollars

For x=1.5, y=0.90

Find the value of the constant of proportionality k

k=y/x ----> k=0.90\1.5=0.6

For x=8, y=4.80

k=y/x ----> k=4.8/8=0.6

The values of k are equal

therefore

This table represent a  proportional relationship between weight and price

<em>Third table </em>

Let

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y ----> the price in dollars

For x=2, y=0.75

Find the value of the constant of proportionality k

k=y/x ----> k=0.75/2=0.375

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k=y/x ----> k=3.75/5=0,75

The values of k are different

therefore

This table not represent a  proportional relationship between weight and price

<em>Fourth table </em>

Let

x ----> the weight in oz

y ----> the price in dollars

For x=2 oz, y=4

Find the value of the constant of proportionality k

k=y/x ----> k=4/2=2

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The values of k are different

therefore

This table not represent a  proportional relationship between weight and price

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3 years ago
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