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3 years ago

Ayudaa con esa qnq -9/4 + 3/7 x -1/11

Mathematics

1 answer:

Nana76 [90]3 years ago

6 0

Answer:

3x-721/44 over 7

Step-by-step explanation:

1)Combine multiplied terms into a single fraction

2)Multiply the numbers

3)Subtract the numbers

4)Find common denominator

5)Combine fractions with common denominator

6)Multiply the numbers

7)Rearrange terms

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The law of cosines is a2+b2-2abcosc=c^2 find the value of 2abcosc

koban [17]

For this case we have the following equation:

$a ^ 2 + b ^ 2-2abcosC = c ^ 2$

To find the value of 2abcosC we must follow the following steps:

Subtract a ^ 2 on both sides of the equation:

$-a ^ 2 + a ^ 2 + b ^ 2-2abcosC = c ^ 2-a ^ 2\\b ^ 2-2abcosC = c ^ 2-a ^ 2$

Subtract b ^ 2 on both sides of the equation:

$-b ^ 2 + b ^ 2-2abcosC = c ^ 2-a ^ 2-b ^ 2\\-2abcosC = c ^ 2-a ^ 2-b ^ 2$

Multiply both sides of the equation by -1:

$(-2abcosC) (- 1) = (c ^ 2-a ^ 2-b ^ 2) (- 1)\\2abcosC = -c ^ 2 + a ^ 2 + b ^ 2$

Answer:

the value of 2abcosC is:

$2abcosC = -c ^ 2 + a ^ 2 + b ^ 2$

6 0

3 years ago

Read 2 more answers

0.15(y-0.2)=2-0.5(1-y)<br><br> The answer is -153/35 I just need to know how to get that

butalik [34]

Answer:

$y=-\dfrac{153}{35}$ .

Step-by-step explanation:

The given equation is

$0.15(y-0.2)=2-0.5(1-y)$

Using distributive property, we get

$0.15(y)+0.15(-0.2)=2-0.5(1)-0.5(-y)$

$0.15y-0.03=2-0.5+0.5y$

$0.15y-0.03=1.5+0.5y$

Isolate variable terms.

$0.15y-0.5y=1.5+0.03$

$-0.35y=1.53$

Divide both sides by -0.35.

$y=\dfrac{1.53}{-0.35}$

$y=-\dfrac{1.53}{0.35}\times \dfrac{100}{100}$

$y=-\dfrac{153}{35}$

Therefore, $y=-\dfrac{153}{35}$ .

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3 years ago

Which of the following is equivalent to (a^1/2*b^1/3)^1/2?

-BARSIC- [3]

Answer:

a^1/4*b^1/6

Step-by-step explanation:

Distribute the 1/2 exponent by multiplying 1/2 by the exponents of the variables

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4 years ago

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