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3 years ago

Ayudaa con esa qnq -9/4 + 3/7 x -1/11

Mathematics

1 answer:

Nana76 [90]3 years ago

6 0

Answer:

3x-721/44 over 7

Step-by-step explanation:

1)Combine multiplied terms into a single fraction

2)Multiply the numbers

3)Subtract the numbers

4)Find common denominator

5)Combine fractions with common denominator

6)Multiply the numbers

7)Rearrange terms

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Just give answers I don't care the explaining just give me the answers I don't want to explain because I'm Savage just give answ

Aneli [31]

3). 9 10/11
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3 years ago

1. The sum of two number is x. If one of the numbers is 16, what is the other number?

Vlada [557]

I hope this helps you

first number 16

second number ?

Sum of these numbers =x

x=16+?

?=x-16

3 0

3 years ago

PLEASE HELP ME OUT!!!

igor_vitrenko [27]

Well, first, the equation that you are looking for is Y = MX + B. To find B, look at the first dot on the Y-axis. It starts at positive 3, so, you know your equation will end with +3. Next, to find MX, start at the either dot, and find the Rise/Run. In this particular equation, the rise is 1, and, the run is -2, because it's going backwards (negative line). Meaning, the line's equation would be, f( x )= -1/2x + 3.

5 0

3 years ago

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GaryK [48]

Answer:

that would be 38 degrees

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (

IrinaVladis [17]

Answer:

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14 and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = $\dfrac{9+9}{2}$

median = $\dfrac{18}{2}$

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = $\dfrac{12+13}{2}$

Median = $\dfrac{25}{2}$

Median = 12.5

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = Q3 - Q1

The interquartile range = 12.5 - 9

The interquartile range = 3.5

7 0

3 years ago