We will consider that earthquakes occurring in a day is a <u>Poisson process</u>. The following Poisson probability distribution formula will be used in this question.

where x = number of outcomes occurring

λ = mean number of occurrences

(a) So, in this question we have λ = 2.5 and we need to find the probability that x=0 (no perceptible earthquakes in a day). So,

P(X=0) = p(0,2.5) = [(e^-2.5)(2.5)⁰]/0!

= ((0.0821)*1)/1

P(X=0) = 0.0821

The probability P of a day with no perceptible earthquakes is 0.0821.

6 0

4 years ago

Can somebody please help with this?

Digiron [165]

Answer:

x=8°

y= 96°

z= 96°

Step-by-step explanation:

Solve for z first. The whole circle is 360° so if you only count half the angles it will add up to 180°.

Solve for z:

48+36+z=180°

84+z+180°

z=96°

Now that you have z you can solve for x by using only the bottom half of the circle.

z+36+6x=180° *remember z=96

96+36+6x=180

132+6x=180

6x=48

x=8°

Now you can solve for y by either plugging x into an equation or by knowing that opposite angles are equal.

y=96°

6 0

4 years ago