Answer:
A) Dimensions;
Length = 20 m and width = 10 m
B) A_max = 200 m²
Step-by-step explanation:
Let x and y represent width and length respectively.
He has 40 metres to use and he wants to enclose 3 sides.
Thus;
2x + y = 40 - - - - (eq 1)
Area of a rectangle = length x width
Thus;
A = xy - - - (eq 2)
From equation 1;
Y = 40 - 2x
Plugging this for y in eq 2;
A = x(40 - 2x)
A = 40x - 2x²
The parabola opens downwards and so the x-value of the maximum point is;
x = -b/2a
Thus;
x = -40/2(-2)
x = 10 m
Put 10 for x in eq 1 to get;
2(10) + y = 40
20 + y = 40
y = 40 - 20
y = 20m
Thus, maximum area is;
A_max = 10 × 20
A_max = 200 m²
32 as well according to some rule in geometry
Answer:
18
Step-by-step explanation:
2(18)=36
because the angles are equal
Answer:
700.4 cm
Step-by-step explanation:
Use a proportion.
Let x be the vertical distance for the 700 cm pipe.
1 cm is to 30 cm as x cm is to 700 cm
1/30 = x/700
30x = 1 * 700
30x = 700
3x = 70
x = 70/3
Now we need l. We have a right triangle with legs measuring 70/3 cm and 700 cm, and we are looking for the hypotenuse l.
a^2 + b^2 = c^2
(70/3)^2 + 700^2 = c^2
c^2 = 4900/9 + 490000
c = 700.4
l = 700.4 cm
