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vitfil [10]
3 years ago
12

Solve the equation: 5 ( x - 2) + 4 ( 3 + x) = 20​

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
4 0

Answer:

the value of x= 2

Step-by-step explanation:

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bixtya [17]3 years ago
3 0

Answer:

x=2

Step-by-step explanation:

5 ( x - 2) + 4 ( 3 + x) = 20​

Distribute

5x -10 +12 +4x = 20

Combine like terms

9x +2 = 20

Subtract 2 from each side

9x+2-2 = 20-2

9x = 18

Divide each side by 9

9x/9 = 18/9

x = 2

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Write 5 consecutive integers of which x is the middle one
stich3 [128]
X-2, x-1, x, x+1, x+2
3 0
3 years ago
(10 points)4 5/6 + 9 5/9 =
lana [24]
14 7/18 is the correct answer i believe.
7 0
3 years ago
Read 2 more answers
. Shanice is making a garden. The area of the garden is 24 ft2. Use the following shape and information to find the base (6−4) a
crimeas [40]

Answer:

The base and height  of the garden are 4.60 ft and 5.60 ft.

Step-by-step explanation:

The area of the garden is, <em>A</em> = 24 ft².

The base height of the garden are:

base (<em>b</em>) = 6x - 4

height (<em>h</em>) = x + 3

Compute the value of <em>x</em> as follows:

A=\frac{1}{2}\times b \times h\\\\24=\frac{1}{2}\times (6x-4) \times (x+3)\\\\48=6x^{2}+18x-4x-12\\\\6x^{2}+14x-60=0\\\\3x^{2}+7x-30=0\\

The last equation is a quadratic equation.

Compute the roots of the quadratic equation as follows:

x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }\\x = \frac{ -14 \pm \sqrt{14^2 - 4(3)(-30)}}{ 2(3) }\\x = \frac{ -14 \pm \sqrt{556}}{ 6 }\\x = \frac{ -14 }{ 6 } \pm \frac{2\sqrt{139}\, }{ 6 }\\x = -\frac{ 7}{  3 } \pm \frac{ \sqrt{139}\, }{  3 }\\x = 1.59661\\x\approx 1.60

The value of base and height are:

\text{base}=6x-4=(6\times 1.60)-4=5.60\ \text{ft}\\\\\text{height}=x+3=1.60+3=4.60\ \text{ft}

Thus, the base and height  of the garden are 4.60 ft and 5.60 ft.

3 0
3 years ago
Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac
melomori [17]
Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ b+c=20
Equation [2] ⇒ 1.50b+5c=54.50

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; b and c, that we need to solve, then this becomes a simultaneous equation problem. 

First, rearrange Equation [1] to make either b or c the subject:
b+c=20
b=20-c

Then we substitute b=20-c into Equation [2]
1.50b+5c=54.50
1.50(20-c)+5c=54.50
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5c-1.5c=54.50-30
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Now we know the value of c which is c=7, substitute this value into b=20-c we have b=20-7=13

Answer:
Numbers of books = 13
Numbers of CDs = 7
5 0
4 years ago
Solve the rational equation x divided by 6 equals x squared divided by quantity x minus 1 end quantity, and check for extraneous
pychu [463]

Answer:

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Step-by-step explanation:

Given:

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\frac{x}{6}=\frac{x^2}{x-1}&#10;

We use the cross multiplication rule and multiply the numerators one side with the denominators of the other side. Therefore,

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Now, for x=0, the rational equation is equal to 0. So, x=0 is a solution.

Also, x=-\frac{1}{5} is also a solution as the equation's denominator is defined at that point.

So, no extraneous solution.

8 0
4 years ago
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