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Brut [27]
3 years ago
12

Write the standard form of an equation with p=12, phi=pi/4

Mathematics
2 answers:
Crank3 years ago
6 0

Answer:

Root 2x plus root 2y-24=0

Step-by-step explanation:

Step 1: Write this formula,

X Cosine Phi + Y Sine of Phi - P = 0

Step  2: input values for x,

X Cosine pi/4 = Root 2/2

Step 3: Input values for Y

Y Sine pi/4=Root 2/2

Step 4: Input P value into the equation

P=12

Step 5:Put the whole thing together

x Root 2/2+ Y Root 2/2-12=0

Take away the denominators and multiply p by 2

you'll get

<u>Root 2X + Root 2Y - 24 =0</u>

Romashka [77]3 years ago
3 0

Answer:

[ - x / 2 - √3 x / 2 - 5 = 0 ]

Step-by-step explanation:

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Plz help I'll give brainlest
jarptica [38.1K]
<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 m^2</h3><h3>3.Area of the trapezoid   = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is  = 1200 square in</h3><h3>8.The area of the rhombus is =84 cm^2</h3><h3>9.Area of the trapezoid  = 240 square ft</h3>

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

                                        =(9×5) m^2

                                         =45 m^2

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                            =\frac{1}{2} \times (12+5) \times 4 square in.

                             = 34 square in.

4.

Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                              =\frac{1}{2} \times (2+6) \times 2 square ft

                              = 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 6\times 9 square cm

                               = 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 12\times 18 square in

                               = 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

                                            = 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = \frac {1}{2} \times 14 \times 12 cm^2

                                         =84 cm^2

9.Given , the base of trapezoid are 24 ft  and 16 ft and height is 12 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                                    = \frac{1}{2} \times (24+16) \times 12 square ft

                                     = 240 square ft

8 0
3 years ago
What is the expression 8(12x+4) equivalent to when x=20?
Elanso [62]
8 ( 12x + 4 ) = 96x + 32                                   8 ( 12x + 4 )
                    = 1920 + 32                   OR      = 8 ( 240 + 32 )
                    = 1952                                       = 1920 + 32
                                                                      = 1952
8*12x = 96x   96*20 = 1920                         
8* 4 = 32                                                       12*20 = 240
                                                                      240*8 = 1920
6 0
2 years ago
Read 2 more answers
How do i solve this?
timofeeve [1]

(f - g)(x) = f(x) - g(x)

… = (3x² - 4) - (4x + 1)

… = 3x² - 4x - 5

3 0
2 years ago
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