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nadezda [96]
2 years ago
10

Please help I’ll give 30 poins

Mathematics
2 answers:
azamat2 years ago
5 0
It will make a cube and the surface area is 125 I believe


5^3=125 therefore the surface area is 125
Jobisdone [24]2 years ago
3 0
Part a= cuboid

Part b= To find the surface area of a cuboid, add the areas of all 6 faces. We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.*I tried my best sorry*
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What is the equation of the graph below? On a coordinate plane, a curve crosses the y-axis at y = 1. It has a maximum of 1 and a
Andreas93 [3]

The equation of the graph is given by y = cos(0.4x) and has an amplitude of 1

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Since the curve crosses the y-axis at y = 1, hence it is a cosine graph. It has a maximum of 1 and a minimum of negative 1, therefore the amplitude is 1

Also, the angular frequency = 2π * 1/5π = 0.4

The equation of the graph is given by y = cos(0.4x) and has an amplitude of 1

Find out more on equation at: brainly.com/question/2972832

#SPJ1

7 0
1 year ago
Please help me <br><br>If 180°&lt;α&lt;270°, cos⁡ α=−8/17, what is sin -α?
rewona [7]

Starting from the fundamental trigonometric equation, we have

\cos^2(\alpha)+\sin^2(\alpha)=1 \iff \sin(\alpha)=\pm\sqrt{1-\cos^2(\alpha)}

Since 180, we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have

\sin(\alpha)=-\sqrt{1-\cos^2(\alpha)}

Plugging the numbers, we have

\sin(\alpha)=-\sqrt{1-\dfrac{64}{289}}=-\sqrt{\dfrac{225}{289}}=-\dfrac{15}{17}

Now, just recall that

\sin(-\alpha)=-\sin(\alpha)

to deduce

\sin(-\alpha)=-\sin(\alpha)=-\left(-\dfrac{15}{17}\right)=\dfrac{15}{17}

6 0
3 years ago
Read 2 more answers
Bonnie withdrew $1,200 from her savings account. She spent 1/5 of the money on travel arrangements. She spent 2/3 of the remaini
svetoff [14.1K]
Withdrew 1200
spent 1/5 on travel : 1/5(1200) = 1200/5 = 240
leaving her with : 1200 - 240 = 960
spent 2/3 on hardware : 2/3(960) = 1920/3 = 640
leaving her with : 960 - 640 = 320
320 - lunch = 300.50
320 - 300.50 = lunch
19.50 = lunch <==
5 0
3 years ago
Read 2 more answers
If the dimensions of a pentagonal prism are quadrupled, then the surface area of the prism is multiplied by eight.
Lubov Fominskaja [6]

Answer:

false

Step-by-step explanation:

the relationship between lengths/dimensions and areas is that areas are created by multiplying 2 dimensions.

when you quadruple (×4) the dimensions, then the areas are growing with the square of the factor (×4×4 = ×16), because the factor goes twice into the multiplication : one time for every dimension involved.

so, quadrupling the dimensions would multiply the areas by 16.

8 0
3 years ago
Sarah is driving. Her distance in km from Tempe after t hours of driving is given by: x = D(t) = 13 + 57t
777dan777 [17]

Answer:

The solutions for your four question problem are:

a) t = D^-1(x) =  (1/57)*x -(13/57)

b) t = D^-1(x) =  1 h

c) D^-1(x) represents time.

d) The number of hours of driving needed for Sarah to be x km from Tempe. (option (c))

Step-by-step explanation:

a) Determine a formula in terms of x for: t = D^-1(x)

The distance in km from Tempe after t hours of driving is given by

x = D(t) = 13 + 57t.

We just need to find the value  t function of x

x = 13 + 57*t

x -13 =  57*t

57*t  = x -13

t = (1/57)*x -(13/57)

We can see the plots of both equation in the picture below.

b) Compute D^-1(70)

Once we find the expression for D^-1(x)

We substitute for x = 70 km

t = D^-1(x) =  (1/57)*x -(13/57)

t = D^-1(x) =  (1/57)*(70) -(13/57)

t = D^-1(x) =  (70/57) -(13/57)

t = D^-1(x) =  (1.228) -(0.228)

t = D^-1(x) = 1 h

c) In the expression D^-1(x) :  what quantity (distance or time) does the x represent?  what quantity (distance or time) does the entire D^-1(x) represent?

x represents Distance in both equations (D(t), and D^-1(x))

t represents Time in both equations (D(t), and D^-1(x))

Since t = D^-1(x),

D^-1(x) represents time.

d) Which of the following statements best describes D^-1(x)?

The number of hours of driving needed for Sarah to be x km from Tempe.

Since, t = D^-1(x), and t represents the amount of time elapsed since Sarah, parted from Tempe, the correct answer is option (c)

The expression for D^-1(x) can be found in the previous answers

t = D^-1(x) =  (1/57)*x -(13/57)

The input is x (distance) and the output is t (time)

6 0
3 years ago
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