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VLD [36.1K]
3 years ago
10

Simplify the following exponential expressions:

Mathematics
2 answers:
slava [35]3 years ago
8 0
30y 1# 24x^7 2# 105m^7 3#.
zhannawk [14.2K]3 years ago
5 0

Answer:

See below

Step-by-step explanation:

1. \: 6 {y}^{3}  \times 5 {y}^{6}  \\  = 6 \times 5 \times  {y}^{3 + 6}   \\ = 30 {y}^{9}  \\  \\ 2. \: 8 {x}^{5}  \times 3 {x}^{2}   \\ = 8 \times 3 \times  {x}^{5 + 2}   \\ = 24 {x}^{7}  \\  \\ 3. \: 7m^4  \times  3m  \times  5m^2  \\ = 105 {m}^{4 + 1 + 2}   \\ = 105 {m}^{7}  \\  \\ 4. \: 10d^7  \times  5d^0 \\  = 10 \times 5 \times  {d}^{7 + 0}  \\  = 50 {d}^{7}

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Simora [160]

The standard form of a quadratic equation is ,

ax² + bx + c = 0.

And the formula to find the discriminant is b² - 4ac.

Here the first step is to change the given equation into standard form. So, add 1 to each sides of the equation. Therefore,

2x² – 9x + 2+1 = –1 + 1

2x² – 9x + 3 = 0

Next step is to compare the given equation with this equation to get the value of a, b and c.

After comparing the equations we will get a = 2, b = -9 and c = 3.

So, discriminant = b²- 4ac

=( -9)²-4 (2)(3)

= 81 - 24

= 57

So, discriminant of the given equation is 57.

57 is greater than 0 and square root of 57 will result real number.

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