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3 years ago

5.

Mathematics

1 answer:

Lostsunrise [7]3 years ago

5 0

Answer:

P) = 1/2 jawbreaker

simplified P) 3/6 = 1/2 jawbreaker

Which both mean the same, so show simplified if asked and either answer if not asked would be marked high.

as 2/6 + 1/3 = 3/6

1 - 3/6 = 3/6

= 1/2 are the workings.

Step-by-step explanation:

Jelly bean = 1/3 = 2/6

Gumdrop = 1/6

2/6 + 1/6 = 3/6 = the difference of 1

1-3/6 = 3/6

Therefore; P) = 3/6 jawbreaker

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Can someone tell me what “increase s by 2s” is

Kryger [21]

Answer:

It means goes up by twos for example 2,4,6,8 all those numbers increase by 2s.

Step-by-step explanation:

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3 years ago

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Help please! How do I graph f(x)=3/4x+2? What points do I plot?

mariarad [96]

(0, 2 ), (4,5)

to draw a graph of a straight line , we only require 2 points

select any 2 values for x, substitute them into the equation for the corresponding y- coordinates

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3 years ago

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2. Evaluate 11h - 6 for when h = 6.

Troyanec [42]

Answer:

Step-by-step explanation:

11*h-6

11*6-6

66-6

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3 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

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3 years ago

A plane begins to descend from a height of 202 meters. The plane decreases in altitude at an average rate of 1.8 meters per seco

stepladder [879]

The plane starts at 202 m.
All altitudes are in meters.
After 1 second, it is at 202 - 1.8
After 2 seconds, it is at 202 - 1.8 * 2
After 3 seconds, it is at 202 - 1.8 * 3
etc.
After x seconds, it is at 202 - 1.8 * x

202 - 1.8 * x is the same as 202 - 1.8x

Answer: F. t(x) = 202 - 1.8x

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3 years ago