Answer:
36 minutes
2 rounds for Priya
3 rounds for Ravish
Step-by-step explanation:
The answer is the LCM (least common multiple) of 12 and 18.
12 = 2^2 x 3
18 = 3^2 x 2
=>LCM of 12 and 18 = 2^2 x 3^2 = 4 x 9 = 36
=> After 36 minutes they meet again at the starting point
=> At that time, Priya has completed: 36/18 = 2 rounds
=> At that time, Ravish has completed: 36/12 = 3 rounds
Answer:
Let's define the variables:
A = price of one adult ticket.
S = price of one student ticket.
We know that:
"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."
1*A + 6*S = $69
"The school took in $150 on the second day by selling 7 adult tickets and student tickets"
7*A + 7*S = $150
Then we have a system of equations:
A + 6*S = $69
7*A + 7*S = $150.
To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:
A = $69 - 6*S
Now let's replace this in the other equation:
7*($69 - 6*S) + 7*S = $150
Now we can solve this for S.
$483 - 42*S + 7*S = $150
$483 - 35*S = $150
$483 - $150 = 35*S
$333 = 35*S
$333/35 = S
$9.51 = S
That we could round to $9.50
That is the price of one student ticket.
She will need 12 seconds because -20•12=-240
Answer:
9,000 x 40 = 360,000
Step-by-step explanation:
9,000 x 40 = 360,000
A one nonzero digit is a number that has only one number that's not 0. For example, 300 has only one nonzero digit.
Hope this helps!
Elimination Method
If we multiply the equation 3 by (-1) we obtain this:
If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z
1. Using the 3rd equation we can obtain X(Y,Z)
2. We can replace this value of X in the 1st and 2nd equations
3. If we simplify:
4. We can obtain Y from this two equations:
5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)
6. If we simplify, we obtain:
7. In conclusion, we obtain that
(X,Y,Z) =
