Question

It is given that the gradient of a straight line which passes through M(h,3) and N(-2,-9) is 2, calculate the value of h.​

Answer 1

Answer:

h = 4

Step-by-step explanation:

Calculate the slope m using the slope formula and equate to 2

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = M (h, 3 ) and (x₂, y₂ ) =  N (- 2, - 9 )

m = $\frac{-9-3}{-2-h}$ = $\frac{-12}{-2-h}$ , then

$\frac{-12}{-2-h}$ = 2 ( multiply both sides by - 2 - h )

2(- 2 - h) = - 12 ( divide both sides by 2 )

- 2 - h = - 6 ( add 2 to both sides )

- h = - 4 ( multiply both sides by - 1 )

h = 4