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3 years ago

A savings account with $1,000 has no other

Mathematics

1 answer:

exis [7]3 years ago

3 0

Answer:

A = P (1 + i)^n where the principal P equals amount A after n periods

P = 1000 and i = .025 / yr

A1 = A (1.025) = 1025

A2 = A1 (1.025) = A (1.025)^2 etc

A5 = A (1.025)^5 = 1000 * (1.025)^5 = 1131 after 5 years

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Express the following as a fraction in its simplest form.

pychu [463]

Given:

Consider the given expression is:

$\dfrac{h+f}{3}+\dfrac{f+k}{2}+\dfrac{4h-k}{5}$

To find:

The simplified form of the given expression.

Solution:

We have,

$\dfrac{h+f}{3}+\dfrac{f+k}{2}+\dfrac{4h-k}{5}$

Taking LCM, we get

$=\dfrac{10(h+f)+15(f+k)+6(4h-k)}{30}$

$=\dfrac{10h+10f+15f+15k+24h-6k}{30}$

$=\dfrac{34h+25f+9k}{30}$

Therefore, the required simplified fraction for the given expression is $\dfrac{34h+25f+9k}{30}$ .

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3 years ago

Sin(60-theta)sin(60+theta)

ehidna [41]

Step-by-step explanation:

$\sin(60 - \theta) \sin(60 + \theta) \\ = \{ \sin(60) \cos( \theta) - \sin( \theta) \cos(60) \} \{ \sin(60) \cos( \theta) + \cos(60) \sin( \theta) \} \\ = \{ \frac{ \sqrt{3} }{2} \cos( \theta) - \frac{1}{2} \sin( \theta) \} \{ \frac{ \sqrt{3} }{2} \cos( \theta) + \frac{1}{2} \sin( \theta) \} \\ \\$

from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

$= \{ {( \frac{ \sqrt{3} }{2}) }^{2} { \cos }^{2} \theta \} - \{ {( \frac{ \sqrt{3} }{2} )}^{2} { \sin }^{2} \theta \} \\ \\ = \frac{3}{4} { \cos }^{2} \theta - \frac{3}{4} { \sin}^{2} \theta$

factorise out ¾ :

$= \frac{3}{4} ( { \cos }^{2} \theta - { \sin}^{2} \theta) \\ \\ = { \boxed{ \frac{3}{4} \cos(2 \theta) }}$

3 0

3 years ago

Read 2 more answers

Answer asap please will mark as brainlist

Leona [35]

Answer:

Exact Form:

√ 30

Decimal Form:

5.47722557 …

Step-by-step explanation: i would go with D

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3 years ago

State the y-coordinate of the y-intercept for the function below.

marta [7]

Answer:

Step-by-step explanation:

y-intercept is defined as the point where the graph crosses the y-axis. The value of x coordinate at this point is zero, as along entire y-axis, the value of x coordinate is always zero. So substituting x = 0 in the function will give us the y-coordinate of the y-intercept of the given function.

$f(x)=x^{3}-x^{2} -x+1$

Substituting x = 0 in this function, we get:

$f(0)=0^{3}-0^{2}-0+1=1$

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3 years ago

Write 17% as a decimal

netineya [11]

0.17

yuh this is correct lol

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3 years ago