5q ≥ 8q - 3/2
<em><u>Add 3/2 to both sides.</u></em>
3/2 + 5q ≥ 8q
<em><u>Subtract 5q from both sides.</u></em>
3/2 ≥ 3q
<em><u>Multiply both sides by 2.</u></em>
3 ≥ 6q
<em><u>Divide both sides by 6.</u></em>
0.5 ≥ q.
The value of q is less than or equal to 0.5.
Sorry im a little late but here's how i did it.
Hope this helps! :)
Answer:
X=9 and X=5
Step-by-step explanation:
So you want to get one side to equal zero so you can factor and find x. I recommend subtracting 14x and adding 45 to both sides so you don't have to deal with a negative quadratic.
X^2 - 14X +45 = 0
Now you can factor. Your looking for two factors that equal 45 and add to -14
All factors of 45:
1 and 45, 3 and 15, 5 and 9, -1 and -45,
-3 and -15, -5 and -9
So out of those combinations -5 and -9 both multiply to 45 and add up to -14 so these are our common factors
(X-5)(X-9)=0
X-5=0 add 5 to both sides X=5
X-9=0 add 9 to both sides X=9
The easiest way is to try the point (-4,1), that is, x=-4, y=1,
to see which equation works.
b works.
The usual way to do it is to find the equation of the circle
standard form of a circle is (x-h)²+(y-k)²=r², (h,k) are the coordinates of the center, r is the radius.
in this case, the center is (-2,1), so (x+2)²+(y-1)²=r²
the given point (-4,1) is for you to find r: (-4+2)²+(1-1)²=r², r=2
so the equation is (x+2)²+(y-1)²=2²
expand it: x²+4x+4+y²-2y+1=4
x²+y²+4x-2y+1=0, which is answer b.
