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2 years ago

NEED HELP PLEASE I need number 3 and 4 please if anybody can help

Mathematics

1 answer:

zepelin [54]2 years ago

6 0

Answer:

top bar on 3. 120 dollars for strawberry milk per month

bottom bar on 3. 100 dollars chocolate milk per month

#4. bars help an individual know information visually and may help an individual understand better.

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1. (2k2+7k4+3) + (2k2-6+6k4)

stellarik [79]

Hope this will help u....:)

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4 0

3 years ago

Read 2 more answers

Is 7/8 a rational number

ohaa [14]

Answer:

true 7/8 is a rational number

6 0

2 years ago

An environmental study of a certain community suggests that t years from now, the average level of carbon monoxide in the air wi

icang [17]

Answer:

3.4625

Step-by-step explanation:

Given the equation:

Q(t)=0.05t^2 + 0.1t + 3.4 parts per million

Where t = time in years

By approximately how much will the carbon monoxide lvel change during the coming 6 months?

t = 6 months = 6/12 = 0.5 year

Q(0.5) = 0.05(0.5)^2 + 0.1(0.5) + 3.4 parts per million

Q(0.5) = 0.05(0.25) + 0.05 + 3.4

Q(0.5) = 0.0125 + 0.05 + 3.4

Q = 3.4625

Carbon monoxide level will change by approximately 3.4625 parts per million in 6 months

7 0

3 years ago

Write an equation in slope-intercept form of the line that passes through the points (- 2, - 2) and (5, 12)

Tasya [4]

Answer:

y= 2 x + 2 i think

Step-by-step explanation:

4 0

2 years ago

Of 900 centimeters. The table shows the height of each bounce.

Mars2501 [29]

Answer:

Rounding to nearest tenth of centimeter, the ball bounces 192.1 cm high on the 5th bounce.

Explanation:

The ball is dropped from a height of 900 centimeters.

Since the heights form a geometric sequence, you can find a common ratio between consecutive terms. This is:

Height bounce 2 / height bounce 1 = 560 / 800 = 0.7

Height bound 3 / height bounce 2 = 392 / 560 = 0.7

Hence, the ratio of the geometric sequence is 0.7, and taking bounce 1 as the start of the sequence, the general term of the sequence is:

$a_n=800(0.7)^{n-1}$

With that formula you can find any term:

$n=1,a_1=800(0.7)^{(1-1)}=800(0.7)^0=800\\ \\ n=2,a_{2}=800(0.7)^{(2-1)}=800(0.7)=560\\ \\n=5,a_{5}=800(0.7)^{(5-1)}=800(0.4)^4=192.08$

Rounding to nearest tenth of centimeter, the ball bounces 192.1 cm high on the 5th bounce.

4 0

3 years ago