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3 years ago

What is 5 pi over 4 radians in degrees?

Mathematics

2 answers:

miss Akunina [59]3 years ago

6 0

The answer to your question is 225 degrees

Gennadij [26K]3 years ago

3 0

Answer:

$\frac{5 \pi}{4}$ radian into degree is, 225

Step-by-step explanation:

To convert radian into degree.

1 radian = $\frac{180}{\pi}$ degree.

Given the statement:

Convert $\frac{5 \pi}{4}$ radian into degree.

Using the conversion:

1 radian = $\frac{180}{\pi}$ degree.

then;

in $\frac{5 \pi}{4}$ radian = $\frac{180}{\pi} \times \frac{5 \pi}{4} = \frac{900}{4} = 225^{\circ}$

Therefore, $\frac{5 \pi}{4}$ radian into degree is, 225

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3 years ago

The sum of three consecutive integers is −42. find the three integers.

erica [24]

Let the integers be x - 1, x and x + 1, then
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3 years ago

I need to find the surface area of the square pyramid! <br> (I know I'm stupid lol)

pogonyaev

Answer:

L = 260 cm^2

Step-by-step explanation:

height h = 12 cm

slant height s = 13 cm

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a = side length

e = lateral edge length

r = a/2

V = volume

L = lateral surface area

B = base surface area

A = total surface area

3 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago