hi
1st draw: green
2/12. (2 green out of 12 marbles), reduces to 1/6
2nd draw: blue
4/11 (4 blue marbles out of the 11 marbles remaining after 1st draw.)
Probability of theses BOTH happening: multiply these individual probabilities.
Conditional probability:
P(a and b) = P(a)P(b|a)
Prob(event 1) × Prob(event 2 given event 1).
1/6 • 4/11 = 4/66 = 2/33 or 0.0606. just a hair over 6% probability of the described sequence hapening.
Answer: I’m pretty sure the answer is S
Answer:
A: 4 miles
B: 3.5 (not sure with this one)
C: 4.5 miles
The answer is 40 because if you multiply 4 times per week× for 10 weeks=40 times for ten weeks.
