-4.5x-2y=-12.5 and 3.25x-y=-0.75
we first multiply the second equation by -2
(-2)*(3.25x-y=-0.75)=-6.5x+2y=-1.5
add the equation to eliminate the y
so yo get (-4.5x-6.5x)=(-12.5-1.5)
-11x=-11
x=1
now we plug in x into any equation to solve for y
-45x-2y=-12.5 and x=1
(-45*1)-2y=-12.5
-4.5-2y=-12.5
-2y=-12.5+4.5
-2y=-8
y=4
then your answer is x=1 and y=4
we can have a triangle and we know that there are two angles.
30º and a 45º + 105 =180º angle. applying the sides.
therefore if we have the whole triangle completed we have a constant triangle.
so it tell us we can you’se SOH CAH TOA
we can varrify what kind of triangle we are using.
for example if we were to use Sin I would do
Sin 30/ 2 = sin of 105º/ A = sin=45º/ B
if you would want to solve for sin 30/2 and sin 105, then we solve.
or Sin 30/2 and Sin 105 as well.
with your calculator use sin= 30=.5 and use sin 105º a divide by 1.5 on both sides 1.5= A /sin 105º * 1.5 answer would be 3.86. a is = to 3.86 (Not the answer)
Answer:
∠J = 60°
Step-by-step explanation:
The Law of Cosines tells you ...
j² = k² +l² -2kl·cos(J)
Solving for J gives ...
J = arccos((k² +l² -j²)/(2kl))
J = arccos((14² +80² -74²)/(2·14·80)) = arccos(1120/2240) = arccos(1/2)
J = 60°
_____
<em>Additional comment</em>
It is pretty rare to find a set of integer side lengths that result in one of the angles of the triangle being a rational number of degrees.
Answer:
The angles are complementary angles because they are 90
Step-by-step explanation:
Dont know a but b is
75=100-2p
75 minus 100 = -25=-2p
-25/-2= p
p=$12.50
