there is not such thing as an I axis, but I will show you what happens for both x and y axis so you can fill out the assignment with the correct information.

IF you meant flipping over the x axis, then the dot will go from top to bottom, bottom to up, the x position won't change only its height(y position)

This meant that for reflecting across the x axis, (x,y)->(x,-y)

For y axis its the opposite, just flipping to the side.

This meant that for reflecting across the y axis, (x,y)->(-x,y)

7 0

3 years ago

25 The library has an empty bookcase with 4 shelves. Each shelf can hold 23 chapter þooks. If the library has 117 new chapter bo

bixtya [17]

Answer:

25 chapter books

Step-by-step explanation:

117 - (23×4)

[23×4=92]

.°. 117 - 92 = 25

7 0

3 years ago

Read 2 more answers

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

3 0

3 years ago