<em> </em><em>The</em><em> </em><em>probability</em><em> </em><em>of</em><em> </em><em>choosing</em><em> </em><em>the</em><em> </em><em>red</em><em> </em><em>shirt</em><em> </em><em>is</em><em> </em><em>1</em><em>/</em><em>1</em><em>0</em><em>.</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
3C
4C
5B (parallel means same slope)
Answer:Well, I don't know what you got so I can't tell you if it is right.
If it works in both equations, it depends of whether your equations are set up correctly.
Here is how I would do this problem.
Let x = no. of hot dogs,y = number of sodas.
First equation is just about the number of things.
x + y = 15
Second equation is about the cost of things.
1.5 x + .75 y = 18
solve x+y = 15 for y y = 15-x substitute into second equation
1.5x + .75(15 - x) = 18
You should get the correct answer for number of hot dogs if you solve this correctly. Put your answer in the x + y =15 equation to get y. Then put both x and y into the cost equation and check your answer.
Hope this helps.
Step-by-step explanation:
Answer:
d≤48/2.15
Step-by-step explanation:
Step one:
Given data
Claudia spends $2.15 a day for lunch.
We are told that her balance is $48.00
let the number of days be d
Step two:
The maximum number of days she can eat is given as
d≤48/2.15
d≤22.33 days
Answer:
P(A∩B) = 0.522
Step-by-step explanation:
Let's call A the event that a puppy is adopted and B the probability that a puppy live 7 or more years
So, the probability P(A∩B) that a randomly selected puppy in the shelter will get adopted and live 7 or more years is:
P(A∩B) = P(A)*P(B/A)
Because A and B are not independents.
Then, the probability P(A) that a puppy is adopted is 58% and the probability P(B/A) that a puppy live 7 or more years given that the puppy is adopted is 90%.
Finally, replacing the values, we get:
P(A∩B) = 0.58*0.9 = 0.522
It means that the 52.2% of the puppies are adopted and live 7 or more years.
