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valina [46]
3 years ago
13

I WILL MARK AS BRAINLIEST! Graph each coordinate pair on the graph and then indicate which quadrant or axis the point lies on.

Mathematics
1 answer:
Kitty [74]3 years ago
7 0

1. 3rd quadrant

2. 3rd quadrant

3. 1st quadrant

4. 1st quadrant

5. 4th quadrant

6. 2nd quadrant

7. 4th quadrant

8. 3rd quadrant

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Luke’s basketball team went to an amusement park at the end of the season. The cost of the admission for 5 coaches and 12 player
Finger [1]

Answer:

The admission cost for each player was <u>22.50</u>.

Step-by-step explanation:

Given:

Luke’s basketball team went to an amusement park at the end of the season.

The cost of the admission for 5 coaches and 12 players was 407.50.

The admission cost for each coach was 27.50.

Now, to find the admission cost for each player.

Total admission cost = 407.50.

Number of coaches = 5.

Admission cost for each = 27.50.

So, the cost of admission of all coaches:

27.50\times 5

=137.50.

Then, we deduct the cost of admission of all coaches from the total admission cost:

407.50-137.50

=270.

<em>Remaining cost = 270.</em>

Number of player = 12.

Now, to get the admission cost for each player we divide the remaining cost  by number of players:

270\div 12

=22.50.

Therefore, the admission cost for each player was 22.50.

7 0
2 years ago
Please help! Name an angle adjacent and congruent to angle AOC ( diagram in picture)
kipiarov [429]

Answer:

Angle DOC

Step-by-step explanation:

Since angle AOC and angle DOC are ajacent angles that form a straight line, they are supplementary to each other.

By the definition of supplementary angles, you can determine that angle AOC + angle DOC = 180.

Also notice that angle DOC is a right angle (90 degrees), so you can also determine that angle AOC is also a right angle since they are supplementary.

7 0
2 years ago
Ik I said one more buh I assure u this is the last :p
Dmitriy789 [7]
Here you go this took me time

3 0
3 years ago
Plz help 20 pts given for the question answered
xxMikexx [17]

Answer:

what question?

Step-by-step explanation:

7 0
3 years ago
Anyone please help!!!
Tanya [424]

Problem 1

Answers:

Percentage of patients that were dogs = 46%

Standard Error = 0.07048404074682

Margin of error for 90% confidence interval = 0.11594624702851

Margin of error for 95% confidence interval = 0.13814871986377

Round the decimal values however you need them

------------

To get the first answer, you add up the numbers given (7,4,5,5,2) and divide that over 50. So 7+4+5+5+2 = 23 which leads to 23/50 = 0.46 = 46%; therefore phat = 0.46 is the sample proportion of dogs.

Use the SE (standard error) formula given to you with phat = 0.46 and n = 50 to get SE = 0.07048404074682

The critical z value at 90% confidence is 1.645; this value is found in your Z table (back of your stats textbook). Multiply the SE value by 1.645 to get 0.07048404074682*1.645 = 0.11594624702851

Also found in your textbook is 1.960 which is the z critical value at 95% confidence. Multiply this with the SE value to get 0.07048404074682*1.960 = 0.13814871986377

===============================================

Problem 2

Answer: Choice B) picking balls from a bin; the 60 randomly selected get chosen for the first bus, while the remaining 60 go to the second bus

-----------

Choice A is fairly vague on what the lower and upper boundaries are. What is the smallest number allowed? What about the largest? This isn't clear so it's possible that we could end up with more positive numbers than negative (eg: if we had an interval -10 < x < 110). So choice A is false. A similar issue shows up with choice D.

Choice B is true. Assuming the selection process is random and not biased, then each ball is equally likely for each selection. The fact that the balls are colored seems to be extra info which I'm not sure why your teacher threw that in there.

Choice C is false because choice B is true

Choice D is false for similar reasons as choice A. It's not clear where we start and where we end. If we had the interval 2 < x < 6 then x could take on the values {3, 4, 5} and we see that picking an odd number is twice as likely than picking an even. In this example, there is bias.

===============================================

Problem 3

Answer: Choice B) Roll a die; each number corresponds to a different class

------------

Choice A is false because choice B being the answer contradicts it

Choice B is true: there are 6 sides on the die, and each side is equally likely to be landed on, so each class is equally likely

Choice C is false because 2*2*2 = 8 represents the number of combos you can have when you flip three coins (one combo being HTH for heads tail heads) but there are 6 classes, not 8

Choice D is false because while we want 6 regions on the spinner. Each region must have the same area; otherwise, one class is weighted heavier than the others making it more likely you select that particular class.


7 0
2 years ago
Read 2 more answers
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