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Ad libitum [116K]
3 years ago
13

What is the value of 500$ invested at 4% interest compounded annually for 7 years

Mathematics
1 answer:
DiKsa [7]3 years ago
5 0

Answer:

657.96

Step-by-step explanation:

use formula A=P(1+r/n)^nt

A=500(1+.04/1)^1*7

A=500(1.04)^7

A=500(1.3159~)

A= 657.96~

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Please HElPPP I AM LITERALLY STUCK
Morgarella [4.7K]
Please see attached photo and give brainliest if you can :) it took me a looong time, hope it helped :)

7 0
3 years ago
Work out the percentage change to 2 decimal places when a price of £57.99 is decreased to £49.99.
IRISSAK [1]

Answer:

Percentage change in price = 13.80%

Step-by-step explanation:

Given that:

Original price = £57.99

Decreased price = £49.99

Difference = Original price - Decreased price

Difference = 57.99 - 49.99

Difference = £8.00

Percent change = \frac{Difference}{Original\ price}100

Percent change = \frac{8.00}{57.99}*100

Percent change in price = 13.80%

Hence,

Percentage change = 13.80%

5 0
3 years ago
Using the laws of indices simplify 625^3/8 ×5^1/2÷ 25​
Oxana [17]

Answer:

1

Step-by-step explanation:

\huge {625}^{ \frac{3}{8} }  \times  {5}^{ \frac{1}{2} }  \div 25 \\  \\ =  \huge {( {5}^{4})}^{ \frac{3}{8} }  \times  {5}^{ \frac{1}{2} }  \div  {5}^{2}  \\  \\  =   \huge{5}^{ \cancel4 \times  \frac{3}{ \cancel8 \:  \:  \red{ \bold 2}} }  \times  {5}^{ \frac{1}{2} }  \div  {5}^{2}  \\  \\   \huge=  {5}^{ \frac{3}{2} }  \times  {5}^{ \frac{1}{2} }  \div  {5}^{2}  \\  \\ \huge=  {5}^{ \frac{3}{2}  + \frac{1}{2}}  \div  {5}^{2}  \\ \\ \huge=  {5}^{ \frac{4}{2}  }  \div  {5}^{2}  \\ \\ \huge=  {5}^{ 2  }  \div  {5}^{2}  \\  \\   \huge=  {5}^{ 2  - 2 }  \\  \\   \huge=  {5}^{ 0 }  \\  \\   \huge=  1

5 0
2 years ago
Help on the second graph
Deffense [45]

Answer:

<u>first graph:</u>

function.

Not one-one

onto

<u>Second graph:</u>

Function

one-one

not onto.

Step-by-step explanation:

We know that a graph is a function if any vertical line parallel to the y-axis should intersect the curve exactly once.

A graph is one-one if any horizontal line parallel to the x-axis or domain should intersect the curve atmost once.

and it is onto if any horizontal line parallel to the domain should intersect the curve atleast once.

Hence, from the <u>first graph:</u>

if we draw a vertical line parallel to the y-axis then it will intersect the graph exactly once. Hence, the graph is a function.

But it is not one-one since any horizontal line parallel to the domain will intersect the curve more than once.

But it is onto, since any horizontal line parallel to the domain will intersect the curve atleast once.

<u>Second graph</u>

It is a function since any vertical line parallel to the co-domain will intersect the curve exactly once.

It is not one-one since any horizontal line parallel to the x-axis does not intersect the graph atmost once.

It is not onto, since any horizontal line parallel to the domain will not  intersect the curve atleast once.

7 0
3 years ago
Does anyone know what has integers as it's square root?
Snezhnost [94]
It shouldn't be too tough to find one of those, seeing that there are
an infinite number of them.

To create one, take any integer, positive or negative, and multiply it by itself.

Here are a few to put you in the mood:

1,  4,  9,  16,  25,  36,  49,  64,  81,  100,  121,  144,  169,  196,  225,  256,  ...

784,  841,  900,  1024,  1225,  1600,  2500,  3600,  4900,  10000,  1 million,  ...

3 0
3 years ago
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