When g ( t ) = 3 t 2 + 2 t + 1 , evaluate g ( − 4 )

Mathematics

2 answers:

Luda [366]3 years ago

7 0

Answer:

Just substitue every 't' with -4

Step-by-step explanation:

g(-4) = 3*(-4)*(-4) + 2*(-4) + 1

g(-4) = 64-8+1

g(-4) = 57

Rus_ich [418]3 years ago

6 0

Answer:

g(-4) is 41

Step-by-step explanation:

$g(t) = 3 {t}^{2} + 2t + 1$

when t is -4, substitute -4 in place of t:

$g( - 4) = 3 {( - 4)}^{2} + 2( - 4) + 1 \\ g( - 4) = 48 - 8 + 1 \\ g( - 4) = 41$

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2,10,18,26 find the 61st term

saw5 [17]

Answer:

482

Step-by-step explanation:

We can see that the numbers shown resemble an arithmetic sequence because they have a common difference. The formula for the nth term of an arithmetic sequence is:

$a_{n} =a_{1} +(n-1)d$

Where $a_{1}$ is the first term, $a_{n}$ is the nth term, and $d$ is the common difference. To find the 61st term, all we need is the first term and the common difference. By looking at what given, we can say the first term is 2. Now, to find the common difference, we find the difference of a term from the term before it. In this case we can do $10-2$ , which is $8$ , or the common difference. Since we have everything we need, it can be plugged into the equation: