Ask question

Ask question

All categories

3 years ago

5

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 70N acts on

a certain object, the acceleration of the object is 7 m/s^2. If the force is changed to 80N , what will be the acceleration of the object?

2 answers:

Anton [14]3 years ago

8 0

Answer:

8 m/s²

Step-by-step explanation:

$F=m*a\\\\70=m*7 \longrightarrow\ m=10 (kg)\\\\80=10*a\longrightarrow\ a=\frac{80}{10}=8(m/s^2)\\$

igor_vitrenko [27]3 years ago

6 0

Answer:

<u>Acceleration</u><u> </u><u>is</u><u> </u><u>8</u><u> </u><u>m</u><u>/</u><u>s²</u>

Step-by-step explanation:

Force = mass × acceleration

${ \sf{F = m \times a}} \\ { \sf{70 = m \times 7}} \\ { \sf{m = 10 \: kg}}$

<u>»</u><u> </u><u>mass</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u> </u><u>kg</u>

when force is 80N:

${ \sf{F = m \times a}} \\ { \sf{80 = 10 \times a}} \\ { \sf{a = \frac{80}{10} }} \\ \\ { \sf{a = 8 \: {ms}^{ - 2} }}$

You might be interested in

Two Integers, a and b, have different signs. The absolute value of integer a is divisible by the absolute

klemol [59]

Answer:

ssorry i am 2ncd grade

Step-by-step explanation:

7 0

4 years ago

Help!!! PLS THIS IS DUE IN 3 hours PLS I BEG OF YOU pls show your work

Shalnov [3]

(A)6x+4x-6=24+9x

10x-6=24+9x

10x-9x=24+6

x=30. (only 1 solution)

(B)25-4x = 15-3x+10-x

25-4x = 5-4x

25-5 = 4x-4x

30 = 0 (No solution)

(C)4x+8 = 2x+7+2x-20

4x+8 = 4x -13

4x-4x = -13-8

0 = -21 (No solution)

6 0

3 years ago

Read 2 more answers

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sampl

kompoz [17]

Complete Question

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sample of 15 students, the professors find the mean number of headaches is 19 and the standard deviation is 1.7. Assume the population distribution of number of headaches is normal.the correct conclusion at $\alpha =0.001$ is?

Answer:

There is no sufficient evidence to support the professor believe

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 18$

The sample size is $n = 15$

The sample mean is $\= x = 19$

The standard deviation is $\sigma = 1.7$

The level of significance is $\alpha = 0.001$

The null hypothesis is $H_o: \mu = 18$

The alternative hypothesis is $H_a : \mu > 18$

The critical value of the level of significance from the normal distribution table is

$Z_{\alpha } = 3.290527$

The test hypothesis is mathematically represented as

$t = \frac{\= x - \mu }{ \frac{\sigma}{ \sqrt{n} } }$

substituting values

$t = \frac{ 19 - 18}{ \frac{1.7}{ \sqrt{15} } }$

$t = 2.28$

Looking at the value of t and $Z_{\alpha }$ we can see that $t < Z_{\alpha }$ so we fail to reject the null hypothesis.

This mean that there is no sufficient evidence to support the professor believe

3 0

4 years ago

I need help please, I am so confused.

vazorg [7]

Answer:

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point: the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward. As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation: $y=x(x-2)$

$\implies x(x-2)=0$

$\implies x=0$

$\implies (x-2)=0 \implies x=2$

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: $y=(x-4)(x+5)$

$\implies (x-4)(x+5)=0$

$\implies (x-4)=0 \implies x=4$

$\implies (x+5)=0 \implies x=-5$

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: $y=-5x(3-x)$

$\implies -5x(3-x)=0$

$\implies -5x=0 \implies x=0$

$\implies (3-x)=0 \implies x=3$

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

4 0

2 years ago

Choose the story that best fits the equation 3/4 • 12=a A). Three out of four students are girls. How many girls are in a group

inessss [21]

Answer:

B

Step-by-step explanation:

we would not be dividing

6 0

3 years ago