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Artemon [7]
3 years ago
12

Marshall lives 2300 yards from school and 1500 yards from the pharmacy. The school, pharmacy, and his home are all collinear, as

shown in the figure.
Geography
2 answers:
lara31 [8.8K]3 years ago
5 0

Answer:

800 yd

Explanation:

AysviL [449]3 years ago
4 0

Answer:

yes they are

Explanation:

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How can i solve the problem and can any onw solve the problem and give me the answer plz
MA_775_DIABLO [31]
No, j=7l because when you plug in the numbers, the equation doesn't work. For example:
j=7l j=2, l=14 
2=7(14)
2=98

The equation should be l=7j j=2, l=14
14=7(2)
14=14

Hope that helps.



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Rochdale is located in Greater Manchester, with a population of 220,000.
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What is the time at hundred degree east when it is 2:00 p.m. at 90 degree east​
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3:oo

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4 0
3 years ago
In nuclear fission and fusion reactions mass is converted into energy. The average person in US uses around 100,000,000 J of ene
daser333 [38]

Answer:

a) The yearly energy consumption for a US population of 300 million is 3\times 10^{16} J/year

b) The energy that would be released if a 60 kg person were converted entirely into energy is 5.4\times 10^{18} Joules.

c) 180 years would this amount of energy support a population of 300 million.

Explanation:

a) Average energy consumed by single person of US = 100,000,000 J/year

Then 300 million US citizen will consume:

300 million = 300 × 1,000,000 = 3\times 10^8

The yearly energy consumption for a US population :

100,000,000 J/year\times 3\times 10^8=3\times 10^{16} J/year

The yearly energy consumption for a US population of 300 million is 3\times 10^{16} J/year

b) E = m\times c^2

E = Energy from converted mass of m

c = speed of light

Given mass of person = m = 60 kg

E=60 kg\times (3\times 10^8 m/s)^2 = 5.4\times 10^{18} J

c) Energy calculated in part (b) = E=5.4\times 10^{18} J

The yearly energy consumption for a US population  of 300 million in an year = 3\times 10^{16} J/year

Let the that would be supported by 5.4\times 10^{18} Joules of energy be x.

x\times 3\times 10^{16} J/year=5.4\times 10^{18} J

x=\frac{5.4\times 10^{18} J}{3\times 10^{16} J/year}=180 years

180 years would this amount of energy support a population of 300 million.

4 0
3 years ago
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