Let
x = larger integer
y = smaller integer
The two integers (x and y) have a sum of 42 which means they add to 42
x+y = 42
solve for y to get
y = 42-x
simply by subtracting x from both sides
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The two integers have a difference of 22. This translates to "subtract the values and the result will be 22", i.e.,
x-y = 22
Plug in y = 42-x. Solve for x
x-y = 22
x-(y) = 22
x - (42-x) = 22
x - 42 + x = 22
2x - 42 = 22
2x - 42+42 = 22+42
2x = 64
2x/2 = 64/2
x = 32
If x = 32, then y is...
y = 42-x
y = 42-32
y = 10
Therefore,
x = 32
y = 10
The final answer is 10
The correct answer to this problem would be d
Answer:
D) The domain of the function is all real numbers
Step-by-step explanation:
Answer:
2x^3−7x^2+16x−15
Step-by-step explanation:
(2x−3)(x^2−2x+5)
=(2x+−3)(x^2+−2x+5)
=(2x)(x^2)+(2x)(−2x)+(2x)(5)+(−3)(x^2)+(−3)(−2x)+(−3)(5)
=2x^3−4x^2+10x−3x^2+6x−15
=2x3−7x2+16x−15
