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DIA [1.3K]
3 years ago
15

Suppose that a computer chip company has just shipped computer chips to a computer company.​ Unfortunately, of the chips are def

ective. ​(a) Compute the probability that two randomly selected chips are defective using conditional probability. ​(b) The probability that the first randomly selected chip is defective is . Compute the probability that two randomly selected chips are defective under the assumption of independent events. ​(a) The probability is nothing. ​(Round to eight decimal places as​ needed.)
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0

Answer:

(a) 0.0000245

(b) 0.000025

Step-by-step explanation:

The complete question is:

Suppose that a computer chip company has just shipped 10,000 computer chips to a computer company. Unfortunately, 50 of the chips are defective. (a) Compute the probability that two randomly selected chips are defective using conditional probability. (b) There are 50 defective chips out of 10,000 shipped. The probability that the first chip randomly selected is defective is  50 /10,000  = 0.005.  Compute the probability that two randomly selected chips are defective under the assumption of independent events.

Solution:

(a)

In this case we need to compute the conditional probability of selecting two defective chips, i.e. the selection of the second defective chip is dependent on the first defective chip.

The probability of selecting the first defective chip is:

P(1D)=\frac{50}{10000}=0.005

Now there are 9999 chips left and 49 defective chips among them.

The probability of selecting the second defective chip is:

P(2D)=\frac{49}{9999}=0.0049

Compute the probability that two randomly selected chips are defective using conditional probability as follows:

P (Two defective chips) =P(1D)\times P(2D)=0.005\times 0.0049=0.0000245

Thus, the answer is 0.0000245.

(b)

Compute the probability that two randomly selected chips are defective under the assumption of independent events as follows:

The above statement implies that the selection was done with replacement.

The probability is:

P (Two defective chips) =P(1D)\times P(2D)

                                      =\frac{50}{10000}\times \frac{50}{10000}\\\\=0.005\times 0.005\\\\=0.000025

Thus, the probability that two randomly selected chips are defective under the assumption of independent events is 0.000025.

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Step-by-step explanation:

I am not sure what you want to calculate as ultimate goal.

but your have an error already in your third line in the picture.

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you had there a "+" instead of a "-".

and then you made subsequent mistakes in every line, some of them are funnily bringing you more back to the real result (e.g. -12i + 12i would be 0 and not -24i, but if the third line would have been correct, then yes, -24i is actually needed) - but not completely.

= 3×2 - 3×4i - 6i×2 + 6i×4i =

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then in the last 3 lines you kind of lose it completely. I am absolutely not sure, what you are calculating, and where the "+" cube from instead of "×" (multiplications) and such.

(3+6i)(2+4i) = 3×2 + 3×4i + 6i×2 + 6i×4i =

= 6 + 12i + 12i + 24×-1 =

= 6 + 24i - 24 = 24i - 18

is that what you wanted to show ?

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Answer:

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Step-by-step explanation:

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