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4 years ago

What is the IQR one, two ,three of u these following numbers 50,70,120,130,145,70,55,45

Mathematics

2 answers:

Softa [21]4 years ago

7 0

50, 70, 120, 130, 145, 70, 55, 45

Put these numbers in order from least to greatest.

45, 50, 55, 70, 70, 120, 130, 145

Q₁=52.5

Median=70

Q₃= 125

~Hope I helped!~

Vanyuwa [196]4 years ago

3 0

Answer:

72.5

Step-by-step explanation:

45, 50, 55, 70, 70, 120, 130, 145

Median: 70

Lower quartile: 52.5

Upper quartile: 125

Interquartile range: 125 - 52.5 = 72.5

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GUYS I NEED HELP ASAP!!!<br><br> Help me solve ?

Shalnov [3]

Solution:

$$h=\frac{ A-2\pi r^2}{2\pi r }$

Given data:

$A=2\pi r^2+2\pi r h$

Let us determine what is h using given A.

$A=2\pi r^2+2\pi r h$

Subtract $2\pi r^2$ on both sides of the expression.

⇒ $A-2\pi r^2=2\pi r^2+2\pi r h-2\pi r^2$

⇒ $A-2\pi r^2=2\pi r^2-2\pi r^2+2\pi r h$

⇒ $A-2\pi r^2=2\pi r h$

Divide both sides of the expression by $2\pi r$ .

$$\frac{ A-2\pi r^2}{2\pi r }=\frac{2\pi rh }{2\pi r }$

$$\frac{ A-2\pi r^2}{2\pi r }=h$

$$h=\frac{ A-2\pi r^2}{2\pi r }$

Option C is the correct answer.

Hence $$h=\frac{ A-2\pi r^2}{2\pi r }$ .

8 0

4 years ago

Five siblings have a combined age of 195 years. The oldest is 13 years older than the youngest Marc the middle child Anne is fiv

lidiya [134]

This is what someone else answered when someone else asked it. I can't explain it better than this.

So five sibbllings ages are repressented as
a,b,c,d,e
let's have a as youngest and e as oldest in that order
total ages are 195 so
a+b+c+d+e=195
oldest is 13 older thatn youngest
e=13+a
middle child anne (c) is 5 years younger than josie who is an unknow position, we know that she could be d or e or oldest or second oldest
the other 2 are 6 years appart
b and d ar e 6 years appart or b and e are 6 years apart? or is josie the oldest, or second oldest?

second oldes is 42 so
d=42

2 scenarios
if josie is oldest, then see AAAA and if josie is second oldest then see BBBB

AAAA
josie is 13 years older than mark
e=13+a
anne is 5 less than josie
c=e-5
the other 2 are 6 years apart
b+6=d
d=42
subsitute and get
b=36
add and get
78+a+c+e=195
a+c+e=117
e-13+e-5+e=117
3e-18=117
add 18 to both sides
3e=135
divided both sides by 3
e=45
subsitute
a=32
b=36
c=40
d=42
e=45

BBBB
oldest is 13 older than youngest
e=13+a
middle is 5 younger than josie (d)
c=d-5
the other 2 are 6 apart
b=e-6
d=42
subsitute
c=37
subsitute
a+b+37+42+e=195
a+b+e+79=195
subtract 79 from both sides
a+b+e=116
subsitute
e-13+e-6+e=116
3e-19=116
add 19 to both sides
3e=135
divide both sides by 3
e=45
subsitute
45-6=39=b
45-13=32=a
c=42-5=37
this is wrong because b cannot be older than c so therefor AAA si the correct answer

THE ANSWER IS
Josie is the oldest=45
Unknown is second oldest=42
Anne is middle=40
Unknown2 is second youngest=36
Mark is the youngest=32

5 0

3 years ago

Answer question 14 please

Fittoniya [83]

Answer:

Step-by-step explanation:

Z is the only relation that does not pass the vertical line test, so Z is not a function.

Answer: D

7 0

2 years ago

Math help Brainliest will be given I solved RS wrong how do I do it I got 112

timurjin [86]

R is between S and T, so this implies that R is on line ST and we can say

SR+RT = ST

plug in the given expressions to get

(-2x+24)+(4x+10) = 4x+12

Now solve for x

(-2x+24)+(4x+10) = 4x+12
-2x+24+4x+10 = 4x+12
2x+34 = 4x+12
2x+34-2x = 4x+12-2x
34 = 2x+12
34-12 = 2x+12-12
22 = 2x
2x = 22
2x/2 = 22/2
x = 11

If x = 11, then RS is,
RS = -2*x+24
RS = -2*11+24
RS = -22+24
RS = 2

-------------------------------------
-------------------------------------

Answers:
x = 11 and RS = 2

3 0

3 years ago

Read 2 more answers

You have $140 in a savings account and save $10 per week. Your friend has $95 in a savings account and saves $19 per week. How m

Dmitry [639]

Answer:

5 weeks

Step-by-step explanation:

19x5=95 95+95=190

10x5=50 50+140=190

7 0

3 years ago