2 cot²(<em>t </em>) sin(<em>t </em>) - cot²(<em>t </em>) = 0
cot²(<em>t </em>) (2 sin(<em>t </em>) - 1) = 0
cot²(<em>t </em>) = 0 <u>or</u> 2 sin(<em>t</em> ) - 1 = 0
cot(<em>t</em> ) = 0 <u>or</u> sin(<em>t</em> ) = 1/2
cos(<em>t</em> ) / sin(<em>t</em> ) = 0 <u>or</u> sin(<em>t</em> ) = 1/2
cos(<em>t</em> ) = 0 <u>or</u> sin(<em>t</em> ) = 1/2
[<em>t</em> = cos⁻¹(0) + 2<em>nπ</em> <u>or</u> <em>t</em> = cos⁻¹(0) - <em>π</em> + 2<em>nπ</em>]
<u>or</u> [<em>t</em> = sin⁻¹(1/2) + 2<em>nπ</em> <u>or</u> <em>t</em> = <em>π</em> - sin⁻¹(1/2) + 2<em>nπ</em>]
(where <em>n</em> is any integer)
<em>t</em> = <em>π</em>/2 + 2<em>nπ</em> <u>or</u> <em>t</em> = -<em>π</em>/2 + 2<em>nπ</em> <u>or</u> <em>t</em> = <em>π</em>/6 + 2<em>nπ</em> <u>or</u> <em>t</em> = 5<em>π</em>/6 + 2<em>nπ</em>
Note that the first two families of solutions overlap and can be condensed, so that
<em>t</em> = <em>π</em>/2 + <em>nπ</em> <u>or</u> <em>t</em> = <em>π</em>/6 + 2<em>nπ</em> <u>or</u> <em>t</em> = 5<em>π</em>/6 + 2<em>nπ</em>
Answer:
The remainder is 0
Step-by-step explanation:
Using the remainder theorem,plug in the zeros of the factor into the polynomial.
The zeros of the factor—›x-1=0,x=1
Plugging 1 into the polynomial
P(1)=2(1)³+(1)²-2(1)-1=0
Number of items an online shopping site sold per second = 420
Number of items it will sell in 30 minutes =
30 minutes = 1800 seconds
Number of items it will sell in 1800 seconds =
= 1800 × 420
= 756,000
∴ This online shopping site will sell 756,000 in 30 minutes .
11n+12- combined like terms