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docker41 [41]
3 years ago
12

Austin invested his saving in two investment found the amount he invested in fund A was 3 times as much as the amount he investe

d in Fund B. Fund A really returned a 6% profit and Fund B returned a 2% profit. How much did he invest in Fund B, if the total profit from the two funds together was $1800
Mathematics
1 answer:
WITCHER [35]3 years ago
6 0

Answer: he invested $9000 in Fund B

Step-by-step explanation:

Let x represent the amount which he invested in the account returning 6% profit.

Let y represent the amount which he invested in the account returning 2% profit.

The amount he invested in fund A was 3 times as much as the amount he invested in Fund B.. This means that

x = 3y

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account returning 6% profit,

P = $x

T = 1 year

R = 6℅

I = (x × 6 × 1)/100 = 0.06x

Considering the account paying 2% interest,

P = $y

T = 1 year

R = 2℅

I = (y × 2 × 1)/100 = 0.02y

if the total profit from the two funds together was $1800, it means that

0.06x + 0.02y = 1800 - - - - - - - - - -1

Substituting x = 3y into equation 1, it becomes

0.06 × 3y + 0.02y = 1800

0.18y + 0.02y = 1800

0.2y = 1800

y = 1800/0.2 = 9000

x = 3y = 3 × 9000

x = 27000

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Answer:

y = 4000 (when x = 0)

Step-by-step explanation:

The initial value of the exponential equation is:

y = 4000\cdot (1.05)^{0}

y = 4000\cdot 1

y = 4000

8 0
3 years ago
What are the x-intercept and the y-intercept of the graph of 9x - 7y = -63?
trasher [3.6K]

Answer:

x-int:  x = -7  and  y-int:  y = 9

Step-by-step explanation:

9x - 7y = -63

x-int:     9x - 0 = -63

x = -7

y-int:   -7y = -63

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7 0
3 years ago
For altitudes up to 36,000 feet, the relationship between ground temperature and atmospheric temperature can be described by the
11Alexandr11 [23.1K]

Given formula : formula t = −0.0035a + g, where t is the atmospheric temperature in degrees Fahrenheit, a is the altitude in feet and g is the ground temperature in degrees Fahrenheit.

To find: 1) If the atmospheric temperature is −25.4 °F and the ground temperature is 60°F, what is the altitude?

2) The equation for a is a = .

Solution: 1) We have atmospheric temperature(t) =−25.4 °F, and

ground temperature(g) =60°F.

Plugging values of t and g in given formula t = −0.0035a + g, we get

-25.4 = −0.0035a + 60.

Subtracting 60 from both sides, we get

-25.4 - 60 = −0.0035a + 60-60

-85.4 = −0.0035a.

Dividing both sides by -0.0035, we get

-85.4/-0.0035 = −0.0035a/-0.0035.

24400 = a

Therefore, if the atmospheric temperature is −25.4 °F and the ground temperature is 60°F, the altitude is 24400 feet.

2) We need to solve equation for a in this part.

We have

t = −0.0035a + g

Subtracting g from both sides, we get

t -g = −0.0035a + g-g

t-g = −0.0035a

Dividing both sides by −0.0035, we get

(t-g)/-0.0035 = −0.0035a/-0.0035

a=-\frac{t-g}{0.0035}

Distributing minus sign on the top, we get

a=\frac{g-t}{0.0035}.

Therefore, the equation for a is a =(g-t)/0.0035.


4 0
3 years ago
Sam is filling up his pool. The water hose filled the 441 gallon pool in 49 minutes. At what rate did the hose fill the pool in
anzhelika [568]

The hose filled up the pool 9 gallons per minute

4 0
3 years ago
Read 2 more answers
Will mark brainliest
crimeas [40]

The answers have been shown below.

<h3>To find the answers:</h3>

Questions regarding the time spent by Jack jogging and bike riding are needed to be answered.

(A) The equations are x+y=75, y=15+x

Time spent jogging is 30 minutes

The total time would be 45+60=105 minutes which is not equal to 75 minutes.

(B) Let x be the time spent jogging.

y be the time spent bike riding.

x+y=75\\y=15+x\\x+15+x=75\\2x+15=75\\x=\frac{75-15}{2} =30

Time spent jogging is 30 minutes.

y=60\\x+y=75

(C) If he rides his bike 15 minutes longer than he jogs then he would have to jog 60-15 = 45 minutes.

Therefore, the total time would be 45+60=105 minutes which is not equal to 75 minutes.

Know more about equations here:

brainly.com/question/2972832

#SPJ4

3 0
2 years ago
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