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3 years ago

How does a degree of a number determine maximum number of zeros?

1 answer:

5 0

Including all real and imaginary zeros and taking multiplicities into account, every equation of degree n has exactly n roots

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Dose anyone know how to solve this?

sesenic [268]

Answer:

AC is double the length of AB

so AC = 12

Step-by-step explanation:

mark me as brainliest ❤️

8 0

3 years ago

A homeowner plans to hang wallpaper on one wall of the bedroom that is 10ft long,if a strip of wall is 20 inches wide and strips

-BARSIC- [3]

Convert 10 ft to inches by multiplying it by 12. That’s 120 inches. Divide this number by 20 inches per strip to get 6 strips needed.

3 0

3 years ago

Read 2 more answers

Nathan usually drinks 36 ounces of water per day. He reads that he should drink 64 ounces per day. If he starts drinking 64 ounc

Paladinen [302]

Questions seems simple but is not

36 ==> 64

About 77% increase

4 0

3 years ago

How can I tell if something is linear or nonlinear?

Anni [7]

Answer:

When something is linear it will meet the criteria, on a graph it will be a straight line, it won't have any curves in it.

When something is nonlinear it doesn't fit the criteria, on a graph it will be curved, never straight

Hope this helps ;)

Step-by-step explanation:

5 0

3 years ago

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The product of (4z^2 + 7z - 8) and (-z + 3) is -4z^3 + xz^2 + yz - 24. What is the value of x? What is the value of y?

ycow [4]

Answer:

$x=5+\frac{29}{z}-\frac{y}{z}$

$y=5z+29-xz$

Step-by-step explanation:

Given: $(4z^2+7z-8)(-z+3)=-4z^3+xz^2+yz-24$ ; find x and y.

Let's start with finding x first. Let's distribute the left side of the equation.

$-4z^3+5z^2+29z-24=-4z^3+xz^2+yz-24$

Let's move everything we can to the left side of the equation. Some things will cancel out.

$5z^2+29z=xz^2+yz$

Now, let's move the term that includes $x$ to the left side of the equation. Everything else should be moved to the right.

$-xz^2=-5z^2-29z+yz$

Let's get rid of the negative sign in front of $x$ by dividing both sides by -1.

$xz^2=5z^2+29z-yz$

To get $x$ completely isolated, divide both sides by $z^2$ .

$\frac{xz^2}{z^2}=\frac{5z^2}{z^2}+\frac{29z}{z^2}-\frac{yz}{z^2}$

Simplify.

$x=5+\frac{29}{z}-\frac{y}{z}$

Let's solve for y. We will start with the distributed and simplified equation to make it easier.

$5z^2+29z=xz^2+yz$

Now, let's move the term that includes $y$ to the left side of the equation. Everything else should be moved to the right.

$-yz=-5z^2-29z+xz^2$

Again, let's get rid of the negative sign in front of the $y$ by dividing both sides by -1.

$yz=5z^2+29z-xz^2$

To isolate y, divide both sides by z.

$\frac{yz}{z}=\frac{5z^2}{z}+\frac{29z}{z}-\frac{xz^2}{z}$

Simplify.

$y=5z+29-xz$

8 0

3 years ago

Read 2 more answers